Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
<h3>
x = 3 units</h3><h3>
</h3>
Step-by-step explanation:
use Pythagorean theorem:
a² + b² = c²
where a = h
b = 8/2 = 4
c = 5
<u>plugin values into the formula:</u>
h² + 4² = 5²
h² = 5² - 4²
x = √9
x = 3
No it can not be formed because the sum of the two smaller side lengths is not greater than the longest length
Answer:
The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.
Step-by-step explanation:
For comparing the mean absolute deviations of both data sets we have to calculate the mean absolute deviation for both data sets first,
So for city 1:



Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored as the deviation is the distance of value from the mean and it cannot be negative. For this purpose absolute is used)

The deviations will be added then.
So the mean absolute deviation for city 1 is 24 ..
For city 2:



Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored)

The deviations will be added then.
So the MAD for city 2 is 11.33 ..
So,
The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.