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3 years ago

I need help on finding the LCD

Mathematics

1 answer:

Kipish [7]3 years ago

6 0

The LCD of the denominator is 12. For this one it is possible to just 'see' that 6 is a divisor of 12. When in doubt, you can always get an answer by just multiplying the denominators. (ie., you can turn 11/12 into 66/72 and 1/6 into 12/72).

In this case, the easiest is to convert 1/6 into 2/12. (multiply both numbers by 2).

Then it becomes:

$9\frac{11}{12} - 9 \frac 2{12} = 9 \frac{11-2}{12} - 9 = \frac9{12} = \frac34$

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3 years ago

The graph of y = f(x) has a maximum point at (-2, 4).

solmaris [256]

Answer:

(2,4).

Step-by-step explanation:

Graph of y = f(-x).

The values of x in f(-x) assume the values of -x in f(x).

For example, f(-2) in f(x) is f(2) in f(-x), and f(2) in f(x) is f(-2) in f(-x).

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3 years ago

From a circular cylinder of diameter 10 cm and height 12 cm are conical cavity of the same base radius and of the same height is

Nataliya [291]

<h3>Volume of the remaining solid = 628 cm^2</h3>

<h3>Whole surface area = 659.4 cm^2</h3>

Step-by-step explanation:

Now, Given that:-

Diameter (d) = 10 cm

So, Radius (r) = 10/2 = 5cm

Height of the cylinder = 12cm.

$volume \: of \: the \: cylinder \: = \pi {r}^{2} h$

$= > \pi \times {5}^{2} \times 12 {cm}^{3} = 300\pi {cm}^{3}$

Radius of the cone = 5 cm.

Height of the cone = 12 cm.

$slant \: height \: of \: the \: cone \: = \sqrt{ {h}^{2} + \: {r}^{2} }$

$= > \sqrt{ {5}^{2}+{12}^{2} } cm \: = 13cm$

Volume of the cone = 1/3 *πr^2h

$= > \frac{1}{3} \pi \times {5}^{2} \times 12 {cm}^{3} = 100\pi {cm}^{3}$

therefore, the volume of the remaining solid

$= 300\pi {cm}^{3} - 100\pi {cm}^{3} \\ = 200 \times 3.14 {cm}^{3} = 628 {cm}^{3}$

Curved surface of the cylinder =

$2\pi \: rh \: = 2\pi \times 5 \times 12 {cm}^{2} \\ = 120\pi {cm}^{2} .$

$curved \: surface \: of \: the \: cone \: = \pi \: rl \\ = \pi \times 5 \times 13 {cm}^{2} \\ = 65\pi {cm }^{2} \\ area \: of \: (upper)circular \: base \: \\ of \: cylinder \: = \\ = \pi \: {r}^{2} = \pi \times {5}^{2}$

therefore, The whole surface area of the remaining solid

= curved surface area of cylinder + curved surface area of cone + area of (upper) circular base of cylinder

$= 120\pi {cm}^{2} + 65\pi {cm }^{2} + 25 \pi {cm}^{2} \\ = 210 \times 3.14 {cm}^{2} = 659.4 {cm}^{2}$

<h3>Hope it helps you!!</h3>

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2 years ago