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2 years ago

Given: m∠A = m∠C = 90° AB ║ DC Prove: ∆ABD ≅ ∆CBD

Mathematics

1 answer:

Genrish500 [490]2 years ago

4 0

Answer:

Angle-Angle-Side (AAS)

Step-by-step explanation:

Given triangles; ΔABD and ΔCBD

<A = <C = $90^{0}$ (right angle property)

AB ║ DC (given)

Then,

DA ║ CB

<B ≅ <D (congruent property)

DB ≅ BD (similarity property)

<D + <B = <B + <D (complementary angles, and property of triangles)

Therefore by Angle-Angle-Side (AAS),

∆ABD ≅ ∆CBD

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Step-by-step explanation:

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Solution to the problem

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Where $\mu=61$ and $\sigma=14$

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