3a-6b/3ab Steps please. Not sure if I originally did this question correctly.

Mathematics

1 answer:

crimeas [40]3 years ago

6 0

Answer:

a-2b/ab

Step-by-step explanation:

3a-6b/3ab

Factorize

3(3a-6b/3ab)

= a-2b/ab

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The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

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Statement is incorrectly written. Correct form is described below:

<em>Find a quadratic polynomial with integer coefficients which has the following real zeros: </em> $x = \frac{2}{9}\pm \frac{\sqrt{23}}{9}$ <em>. </em>

Let be $r_{1} = \frac{2}{9}+\frac{\sqrt{23}}{9}$ and $r_{2} = \frac{2}{9}-\frac{\sqrt{23}}{9}$ roots of the quadratic function. By Algebra we know that: