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3 years ago

Someone help please this is for trigonometry

Mathematics

1 answer:

Softa [21]3 years ago

4 0

Hi there!

Something really good to remember about trigonometry is SOHCAHTOA. I won’t dive into too much detail about it, but you should google it for future assignments.

Anyways,

tan50°=14/AB
ABtan50°=14
AB=14/tan50°
AB=11.75

cos50°=14/AC
ACcos50°=14
AC=14/cos50°
AC=21.78

For the measure of angle C you can use a theorem called the third angle theorem. In every single possible triangle, the sum of all three angles adds up to 180°. You can set up an equation like so...

angleC=180-(90+50)
angleC=180-140
angleC=40°

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Answer:

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3 years ago

Read 2 more answers

De los 125 alumnos que hay en 5 grado, 3/4 de ellos tienen celular. Cuántos alumnos no tienen celular?

bogdanovich [222]

Answer:

31 alumnos no tienen celular

Step-by-step explanation:

Si 3/4 de los alumnos tienen celular, entonces 1/4 de ellos no tienen celular.

1/4 de 125 =

= 0.25 * 125

= 31.25

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3 years ago

Evaluate this exponential expression (27/8)^ 4/3<br><br> A: 9/2<br> B: 4/3<br> C: 81/16

valkas [14]

$\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \left( \cfrac{27}{8} \right)^{\frac{4}{3}}\implies \left( \cfrac{3^3}{2^3} \right)^{\frac{4}{3}}\implies \left( \cfrac{3^{3\cdot \frac{4}{3}}}{2^{3\cdot \frac{4}{3}}} \right)\implies \cfrac{3^4}{2^4}\implies \cfrac{81}{16}$

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3 years ago

Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.

fgiga [73]

Answer:

QN = 3√7
OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

DQ = (3 units)·3 = 9 units

KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

KI² = KO² +OI²

4² = 3² +OI²

OI = √(16 -9)

OI = √7

QN = 3·OI = 3√7

8 0

3 years ago