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Illusion [34]
3 years ago
13

HELP ASAP

Mathematics
1 answer:
atroni [7]3 years ago
3 0
The answer to your question is B.
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A rectangle has a width of 46 centimeters and a perimeter of 208 centimeters. What is the rectangles length
alexdok [17]
208- ( 2* 46)= X
208- 92=2x
x=58

The length is 58cm.

Check by:
58*2 +46*2
116+92= 208
4 0
3 years ago
Write an equation of the line with the given slope that contains the given point.
Alchen [17]

Answer:

y=-2x+12

Step-by-step explanation:

We can use the point-slope form given by:

y-y_1=m(x-x_1)

Where <em>m</em> is the slope and (x₁, y₁) is a point.

So, we will substitute -2 for <em>m</em> and (5, 2) for (x₁, y₁). This gives us:

y-(2)=-2(x-(5))

Simplify:

y-2=-2(x-5)

Distribute:

y-2=-2x+10

Add 2 to both sides. Hence, our equation is:

y=-2x+12

3 0
3 years ago
The function f is continuous on the closed interval [1,15] and has the values shown on the table above. Let g(x) = ∫f(t) dt [1,x
Anna11 [10]
We're looking for the two values being subtracted here. One of these values is easy to find:

<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
 
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:

</span><span>Each integral breaks down like so:

(3-1)*f(1)=4

(6-3)*f(3)=9

(10-6)*f(6)=16

(15-10)*f(10)=10.

So, the sum of all these integrals is 39, which means g(15)=39.
 
Then, g(15)-g(1)=39-0=39.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
3 0
3 years ago
Read 2 more answers
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
1. What is the value of the expression f2 + 5 if f = 3?<br> A. 8<br> B. 2<br> C. 6<br> D. 14
zaharov [31]

Option D: 14 is the right answer

Step-by-step explanation:

In order to find the value of given expression we have to put the given value for f in the expression

Given expression is:

f^2+5

We have to find the value of expression on f=3

So,

putting f=3 in expression

= (3)^2+5\\= 9+5\\=14

The value of given expression at f=3 is 14

Hence,

Option D: 14 is the right answer

Keywords: expressions, variables

Learn more about expressions at:

  • brainly.com/question/10364988
  • brainly.com/question/10435816

#LearnwithBrainly

8 0
3 years ago
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