The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
Answer:
5.41 m
Step-by-step explanation:
First, let's find a side length by taking the square root of the area.
117/64 ^ 1/2 = 1.352...
Next, we need to multiply by 4.
1.352... x 4 = 5.408...
= approximately 5.41
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For this case the area is given by:
A = (22 + x) * (28 + x) = 722
Rewriting we have:
616 + 22x + 28x + x ^ 2 = 722
x ^ 2 + 50x + 616 - 722 = 0
x ^ 2 + 50x - 106 = 0
Solving the polynomial we have:
x1 = 2.04
x2 = -52.04
We take the positive root:
x = 2.04 inches:
Answer:
The width of the border to the nearest inch is:
x = 2inches
Answer:
16 times
Step-by-step explanation:
13 + 4 +8 = 25 total marbles
(4 is total number of blue marbles, 25 is complete total of marbles)
4/25 times = ?/100 times
Because 25 times 4 is equal to 100, you then multiply 4 by 4 to get 16
16/100 times
Answer:
<h2>12.56</h2>
Step-by-step explanation:
2 x 2 x 3.14 = 12.56
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