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aleksklad [387]
2 years ago
8

Consider quadrilateral BCEF inscribed in circle A. Diagonals EB and CF intersect at point D. Select all the statements that are

true about the diagram above

Mathematics
1 answer:
Elena L [17]2 years ago
6 0

Answer:

m\angle ECB+m\angle EFB=180

m\angle CDB\cong m\angle EDF

m\angle CDB+m\angle DCB+m\angle CBD=180 \degree

Step-by-step explanation:

From the diagram, quadrilateral BCEF is a cyclic quadrilateral.

Opposite angles if a cyclic quadrilateral sum up to 180°

m\angle ECB+m\angle EFB=180

The diagonals intersect at D to form two pairs of vertical angles, and vertical angles are congruent.

m\angle CDB\cong m\angle EDF

Also sum of angles in triangle CBD is 180°.

m\angle CDB+m\angle DCB+m\angle CBD=180 \degree

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Step-by-step explanation:

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Use the GCF and distribute property to express the sum as a product 20+60
kenny6666 [7]
20(1+3)

The greatest common factor between the two numbers is 20, because both numbers are divisible by 20. It cannot be any higher because 20 is one of the numbers itself. You divide this out of both numbers and put it outside the function with the use of parenthesis. 
8 0
3 years ago
How do ypu slove dis? <br>y^2(q-4) - c(q - 4)
Annette [7]
<span><span> y2(q-4)-c(q-4)</span> </span>Final result :<span> (q - 4) • (y2 - c) </span>

Step by step solution :<span>Step  1  :</span><span>Equation at the end of step  1  :</span><span><span> ((y2) • (q - 4)) - c • (q - 4) </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span> y2 • (q - 4) - c • (q - 4) </span><span>Step  3  :</span>Pulling out like terms :

<span> 3.1 </span>     Pull out     q-4 

After pulling out, we are left with : 
      (q-4) • (<span> y2</span>  *  1 +( c  *  (-1) ))

Trying to factor as a Difference of Squares :

<span> 3.2 </span>     Factoring: <span> y2-c</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 <span>- AB + AB </span>- B2 = 
        <span> A2 - B2</span>

</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check : <span> y2  </span>is the square of <span> y1 </span>

Check :<span> <span> c1  </span> is not a square !! 
</span>Ruling : Binomial can not be factored as the difference of two perfect squares

Final result :<span> (q - 4) • (y2 - c) </span><span>
</span>
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Step-by-step explanation:


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