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3 years ago

The radius of a circle is 9 centimeters what is the circles circumference

Mathematics

2 answers:

kifflom [539]3 years ago

8 0

Answer:

18π cm or 56.52cm

Step-by-step explanation:

Circumference = 2πr

2π(9)

18π

18π = 56.52

neonofarm [45]3 years ago

6 0

Answer:

56.55

Step-by-step explanation:

C=2πr=2·π·9≈56.54867

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Choose the values of the range given the function below. {(-1, -3), (5,7). (8. -4), (-7, 3), (-5, 11)}

lyudmila [28]

Answer:

the answer is 53454

Step-by-step explanation:

1+1=1

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3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

NO SOLUTION

7 0

3 years ago

Lynn plotted point G, 3 units to the left and 2 units above point F . Where did Lynn plot point G ?

bekas [8.4K]

Answer:

(2, 6)

Step-by-step explanation:

Point G has a coordinate of x = 5, and y = 4, that is (5, 4).

If Lynn plots point G, such that:

G is 3 units to the left of point F, the x-coordinate of point G = 5 - 3 = 2

G is 2 units above point F, the y-coordinate of point G = 4 + 2 = 6.

Therefore, Lynn plotted point G at x = 2, and y = 6. Which is (2, 6)

3 0

3 years ago

The horizontal distance of the ramp is 12 ft. And the vertical height of the ramp is 5 ft. Round answers to the nearest whole nu

Elan Coil [88]

Answer:

The length of the ramp is 13 ft according to the Pythagorean theorem but I don't have an idea about the angle incline.. we must trigonometry to find it .

7 0

3 years ago

Read 2 more answers

GEOMETRY PROOFS!

NeX [460]

From the given figure ,

RECA is a quadrilateral

RC divides it into two parts

From the triangles , ∆REC and ∆RAC

RE = RA (Given)

angle CRE = angle CRA (Given)

RC = RC (Common side)

Therefore, ∆REC is Congruent to ∆RAC

∆REC =~ ∆RAC by SAS Property

⇛CE = CA (Congruent parts in a congruent triangles)

Hence , Proved

Additional comment:-

SAS property:-

"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)

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6 0

2 years ago