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klemol [59]
3 years ago
13

PLSSSS HELPPPP MEEE I WIIILLL GIVVEEE BRAINLIEST!!!!!!!!!!!!!

Mathematics
2 answers:
kirill115 [55]3 years ago
7 0

Answer:

slope m = 0

Step-by-step explanation:

To find the slope for two points, you need use

m = (y2 - y1)/(x2-x1)

for point 1 (-1, -4) and point 2 (-2, -4)

m = (-4 - (-4)) / ((-2)-(-1))

m = 0 / -1

when the top number is zero, the answer is 0

if you plot the points in a graph, it is a horizontal line or y = mx + b = 0m -4

y = -4

grigory [225]3 years ago
6 0

Answer:

y - y1 = m( x- x1) - this is the formula to be used whenever looking for a slope of points.

from the coordinates choose the points which will be your x, y and the points which will be your x1,y1

then solve for m.

m is the slope.

(-1,-4) are my x, y

(-2,-4) are my x1, y1

then

-4 - (-4) = m(-1 -(-2))

open the brackets

-4 + 4 = m ( -1 +2)

0 = m( 1)

m = 0

slope is 0

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What is the slope of the line that passes through the points listed in the table?
brilliants [131]

Answer:

B. 2

Step-by-step explanation:

(4, 3) (7, 9)     M = Slope

M = \frac{y^2-y^1}{x^2-x^1}      Slope formula

M=\frac{9-3}{7-4}       Using the slope formula, plot both x and y intercepts

M=\frac{6}{3}           Slope needs to be simplified into a whole number

M=2          

4 0
2 years ago
Jen borrowed 1500 from her parents for car repair. She plans to take 10% of her $450 weekly income to pay them back. At this rat
7nadin3 [17]

Answer:

10% of %450 is $45

SO 1500 divide by $45 is 33.33333

SO it will take a little over 33 weeks

Step-by-step explanation:


5 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
A map has a scale of
givi [52]
For ever 4 inches, you have 25 miles. Therefore if you have only one, you multiply to find the other. Now, since you have miles, you need to find inches. Therefore, 120 divided by 4, because every 4 inches is equal to 25 miles. Your answer should be 30 inches
3 0
3 years ago
timomthy began his math homework at 5:17 pm he finished at 5:49 how many minutes did he send on his math homework
daser333 [38]

Answer:

32 minutes

Step-by-step explanation:

49 - 17 = 32

Timothy spent 32 minutes on his math homework.

3 0
2 years ago
Read 2 more answers
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