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3 years ago

Find the value of x it y so that line through the points has the given slope

Mathematics

1 answer:

svetlana [45]3 years ago

3 0

Set up slope formula and solved for x.

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) What would the value of c be when

jasenka [17]

The value of c is 233.3

Step-by-step explanation:

Given equation is:

$\frac{18}{20}c-250=-40$

To find the value of c, we have to isolate c on one side of the equation

So,

Adding 250 on both sides

$\frac{18}{20}c-250+250=-40+250\\\frac{18}{20}c=210$

Multiplying by 20 on both sides

$20*\frac{18}{20}c=210*20\\18c=4200$

Dividing both sides by 18

$\frac{18c}{18}=\frac{4200}{18}\\c=233.3333$

Rounding off to the nearest one decimal place

c=233.3

The value of c is 233.3

Keywords: Linear Equation, Solution of linear equation

Learn more about linear equations at:

#LearnwithBrainly

3 0

3 years ago

If cos(θ)=2853 with θin Q IV, what is sin(θ)?

marysya [2.9K]

Answer: $\sin \theta=\frac{-45}{53}$

Step-by-step explanation:

Since we have given that

$\cos\theta=\frac{28}{53}$

And we know that θ is in the Fourth Quadrant.

So, Except cosθ and sec θ, all trigonometric ratios will be negative.

As we know the "Trigonometric Identity":

$\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}$

It must be negative due to its presence in Fourth quadrant.

Hence, $\sin \theta=\frac{-45}{53}$

7 0

3 years ago

According to a state law for vehicles traveling on state roads, the maximum total weight of a vehicle and its contents depends o

Alex787 [66]

Inequalities are used to show the relationship between unequal expressions.

The inequalities that represent the maximum weights are:

2 axles - $x \le 40000$ .
3 axles - $x \le 60000$ .
4 axles - $x \le 80000$ .

Let the maximum weight be represented with x

In inequality, maximum means less than or equal to i.e. $\le$

(a) 2 axles

The maximum weight, here is 40000.

So, the inequality is:

$x \le 40000$

(b) 3 axles

The maximum weight, here is 60000.

So, the inequality is:

$x \le 60000$

(c) 4 axles

The maximum weight, here is 80000.

So, the inequality is:

$x \le 80000$

See attachment for the graphs of each inequality