During a group project, two students constructed a simple machine to add to their Rube Goldberg project. They were told to creat
2 answers:
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Given:
Mass of the rail road car, m = 2 kg
velocity of the three cars coupled system, v' = 1.20 m/s
velocity of first car, = 3 m/s
Solution:
a) Momentum of a body of mass 'm' and velocity 'v' is given by:
p = mv
Now for the coupled system according to law of conservation of momentum, total momentum of a system before and after collision remain conserved:
(1)
where,
= velocity of the first car
= velocity of the 2 coupled cars after collision
Now, from eqn (1)
v' = 1.80 m/s
Therefore, the velocity of the combined car system after collision is 1.80 m/s
Answer: 9.33fm
Explanation:
Similarly as with a cut diffraction happens when part of the proliferating wave is cut off. This will occur for any object of request with a similar size as the wavelength of the diffracting wave.
Note, the object is moving at 14% of the speed of light. Be that as it may, the gamma factor is just 1% so taking care of the issue either relativistic or non relativistic conditions offers comparative responses.
Note: The size of the object has to be of the order of the wavelength of 10MeV. Therefore, size apperture that would be necessary to observe diffraction effect would be 9.33fm.
The calculations are in the attachment below:
