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mariarad [96]
3 years ago
6

Can someone plz help me

Physics
1 answer:
Ymorist [56]3 years ago
6 0

∆ STRONG ACIDS :

• SULPERIC ACID

• HYDROCHLORIC ACID

• NITRIC ACID

∆ STRONG BASES :

• SODIUM HYDROXIDE

• POTASSIUM HYDROXIDE

• CALCIUM HYDROXIDE

• BARIUM HYDROXIDE

∆ WEAK ACIDS :

• ACETIC ACID

• PHOSPERIC ACID

• FORMIC ACID

∆ WEAK BASES :

• ANMONIUM HYDROXIDE

• MAGNESIUM HYDROXIDE

• SODIUM HYDROXIDE

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A 12.0 kg block rests on an inclined plane. The plane makes an angle of 31.0° with the horizontal, and the coefficient of fricti
allochka39001 [22]

Answer:

The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

Explanation:

Given that,

Mass = 12.0 kg

Angle = 31.0°

Friction coefficient = 0.158

Mass of second block = 38.0 kg

Using formula of frictional force

f_{\mu} = \mu N....(I)

Where, N = normal force

N = mg\cos\theta

Put the value of N into the formula

N =12\times9.8\times\cos 31^{\circ}

N=100.80\ N

Put the value of N in equation (I)

f_{mu}=0.158\times100.80

f_{mu}=15.9264\ N

Now, Weight of second block

W = mg

W=38.0\times9.8

W=372.4\ N

The horizontal force is

F = mg\sintheta

F=12\times9.8\times\sin 31^{\circ}

F=60.5684\ N....(II)

(I). We need to calculate the acceleration

a=m_{2}g-\dfrac{f_{\mu}+mg\sin\theta}{m_{1}+m_{2}}

a=\dfrac{372.4-(15.9264+60.5684)}{12+38}

a=5.92\ m/s^2

(II). We need to calculate the tension in the rope

m_{2}g-T=m_{2}a

-T=38\times5.92-38\times9.8

T=147.44\ N

Hence, The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

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The  gap should be filled with an apparent upward

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The Doppler effect can be observed to occur with all types of waves - most notably water waves, sound waves, and light waves

The Doppler effect describes sound as an effect which is produced from a moving source of wave.

According to the Doppler effect;

When the source of waves in which there is an apparent upward shift in frequency for observers towards whom the source is approaching.

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