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ArbitrLikvidat [17]

3 years ago

5

many interactions occur among systems, such as the atmosphere , biosphere, hydrosphere, and geosphere. Of the systems mentioned

which scenario describes an interaction between two different “spheres”.

1 answer:

posledela3 years ago

5 0

I’d put atmosphere.

Hope it works!

Mark me as brainliest pls!

Good luck :)

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before dancing on a smooth wooden floor, ballet dancers sometimes sometimes put a sticky powered called rosin on their shoes sol

Katena32 [7]

Okay, so they want to basically Increase their grip, and they are taking advantage of the force of friction

3 0

2 years ago

In a fireworks display, a rocket is launched from the ground with a speed of 18.0 m/s and a direction of 51.0° above the horizon

Masja [62]

Answer:38.66 m

Explanation:

Given

launch angle $\theta =51^{\circ}$

launch velocity $u=18 m/s$

center of mass continue to travel its original Path so it center of mass will be at a distance of

$R=\frac{u^2\sin 2\theta }{g}$

$R=\frac{18^2\sin 102}{9.8}$

$R=32.33 m$

Center of mass will be at $x=32.33 m$

(b)if one of the piece will be at x=26 m then other will be at

$x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}$

$x_{com}=\frac{\frac{m}{2}\cdot 26+\frac{m}{2}\cdot x_0}{\frac{m}{2}+\frac{m}{2}}$

$32.33=\frac{26+x_0}{2}$

$x_0=38.66 m$

8 0

3 years ago

Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up

kirza4 [7]

Answer:

I believe the answer is b

Explanation:

5 0

3 years ago

What does an Astronomer study? *

ratelena [41]

Answer:

an astronomer studies planets, stars, moons, etc, or objects that are outside the field of Earth.

3 0

4 years ago

A ship leaves a harbor and sails at 23.5 ∘ to the north of due west. After traveling 575 km, how far west is the ship from the h

solniwko [45]

Answer:

D = 527.31 Km

Explanation:

given,

angle of ship, θ = 23.5° N of W

distance travel in the direction = 575 Km

Distance of ship in west from harbor = ?

now,

Distance of the ship in the west direction

D = d cos θ

d = 575 Km

θ = 23.5°

inserting all the values

D = 575 x cos 23.5°

D = 575 x 0.91706

D = 527.31 Km

Hence, the distance travel by the ship in west from harbor is equal to D = 527.31 Km

6 0

3 years ago