Answer:
F = 3.98 kN
Explanation:
GIVEN DATA:
sides of box = 17 cm
pressure = 1 atm = 101325 N/m2
T2 = 378K
T1 = 278 K
final pressure can be calculate by using below relation
we know that
force = pressure * area
therefore force is
F = 3.98 kN
Answer:
Fall at equal acceleration with similar displacements.
Explanation:
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Objects under free fall with no air resistance, are falling under the sole influence of gravity. So, under that conditions, objects with different masses will fall with the same rate of acceleration
Answer:
This is net charge on the surface is Q = σ₀ x (y + 2by²)
Explanation:
The surface charge density is defined as the amount of charge Q per unit area A
σ = dq / dA
dq = σ dA
Since the surface is a rectangular region we use an xy coordinate system so the area difference
dA = dxdy
dq = σ dx dy
We replace, evaluate the integral
∫ dq = ∫ σ₀ (1 + yb) dxdy
realizamos laintegral de dx
Q -0 =σ₀ ∫ (1 + yb) (x-0) dy
Where we evaluate We must recognize that the charge Q must be zero by the time X = 0 and Y = 0. At the starting point Q = 0 for x = 0
We perform the other integral (dy)
Q = σ₀ x (y + 2y² b)
Evaluated between Y = 0 and Y = y
Q = σ₀ x (y + 2by²)
This is net charge on the surface
Answer:
vf = 14.2176 m/s
Explanation:
Given
m = 4 Kg
viy = 7.00 ĵ m/s
Fx = 11.0 î N
t = 4.5 s
vf = ?
Using the Impulse - Momentum Theorem, we have
F*Δt = m*Δv ⇒ F*Δt = m*(vf - vi)
⇒ vf = (F*Δt + m*vi) / m
⇒ vf = (F*Δt + m*vi) / m
For <em>x-component</em>
⇒ vfx = (Fx*Δt + m*vix) / m = (11 N*4.5 s + 4 Kg*0 m/s) / (4 Kg)
⇒ vfx = 12.375 î m/s
For <em>y-component</em>
⇒ vfy = (Fy*Δt + m*viy) / m = (0 N*4.5 s + 4 Kg*7 m/s) / (4 Kg)
⇒ vfy = 7 ĵ m/s
Finally:
vf = √(vfx² + vfy²)
⇒ vf = √((12.375 m/s)² + (7 m/s)²)
⇒ vf = 14.2176 m/s
