HELP TIMED 20 MIN LEFT BRAIBLIST

dedylja [7]

First you want to get it to y=mx+b. to do this you have to get the y by itself on one side. 2x-5y=7 you bring -5y over and get 2x=5y+7. Then bring the 7 over and get 2x-7=5y and finally get rid of the 5 by dividing both sides by it 2x-7/5 turns into 2/5x-7/5 and 5y becomes y. Y=2/5X-7/5. Next to get the slope of a line perpendicular to another you first flip the original slope (2/5x to 5/2x) and then reverse the sign (5/2x to -5/2x). and now you have Y=-5/2X+B. To get B you must put in what you know (X is 4, Y is 3) Get 3=-5/2(4)+B and solve.
3=-5/2(4)+B to 3=-10+B. bring -10 over and get 13=B and put that in. Finally you have Y=-5/2X+13.

8 0

3 years ago

Simplify this rational expression. 2x^2+5x+3/2x^2-x-3

Murljashka [212]

Answer:

$2x+3$ / $2x-3$

Step-by-step explanation:

firstly we make two steps to simplify this question.

1st step: simplify $2x^{2} +5x+3$

to simplify this we use factorization

$2x^{2} +2x+3x+3$

$2x(x+1) +3(x+1)$

$(2x+3) (x+1)$ .....(1)

2nd step:simplify $2x^{2} -x-3$

$2x^{2} +2x-3x-3$

$2x(x+1)-3(x+1)$

$(2x-3)(x+1)$ .....(2)

now dividing (1) and (2), we get the answer

$2x+3/2x-3$

5 0

2 years ago

Urgent math help needed will mark brainliest

iren [92.7K]

Remark

Many calculators have a key that will do this in one step. Mine is one of them. So let's start with the answer and then we'll do it the long way.

9C3 = 84. You put it into your calculator as 9 2nF nCr 3 =

Solution

$\dfrac{9!}{(n - 3)!3!} = \dfrac{9*8*7*6!}{6!*3!}=\dfrac{9*8*7}{6}$

3*4*7 = 84 which is what you set out to show.

3 0

3 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

6 0

3 years ago

PLEASE ANSWER ASAP! YOUR ANSWER MUST INCLUDE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST! THANKS!!!

7nadin3 [17]

The equation formula of the circle is (x-h)^2 + (y-k)^2 = r^2
where (h,k) the point of the center of the circle
and (r) is the radius of the circle
so if the center of the circle = (-2,-4)
by subs. in the formula we get (x-(-2))^2 + (y-(-4))^2 = r^2
then the equation will be (x+2)^2 + (y+4)^2 = r^2
now we want to define the radius of the circle r
since point (3,8) lay on the circle so we can
then subs. in the equation to get the radius
(x+2)^2 +(y+4)^2 = r^2
(3+2)^2 +(8+4)^2 = r^2
25 + 144 = r^2
r^2 = 169
r= 13
the radius of the circle is 13
so by subs in the equation we get
(x+2)^2 + (y+4)^2 = 169
so it is the first answer in the choices

8 0

3 years ago