Answer:
(1/2)s = 345
s = 690 (Maggie's savings balance)
Step-by-step explanation:
For any problem, word problem or otherwise, you start be reading and understanding the problem. You should specifically look for
- what you're being asked to find (what is the question to answer)
- the information you're given that is relevant to the question asked.
Here, you're asked to find a savings account balance. You're told that $345 is half that amount.
__
After you decide what you're looking for and the given relevant information, you use the problem statement and your personal knowledge to write one or more equations relating what you know to what you want to find.
A first step for doing this is to define any necessary variables. In this problem, we can use "s" for the original savings balance (in dollars). (I like to choose letters that remind me what they stand for. "x" or "y" can sometimes get mixed up. For a one-variable problem, it doesn't really matter what you call it. It is helpful to be clear about the units of measure of any variables. Confusion there can also lead to errors.)
The problem statement tells us that half the savings account amount is $345, so our equation is ...
(1/2)s = 345
__
The "one step" required to solve this so to multiply both sides of the equation by 2.
s = 690
Maggie had $690 in her savings account before she bought the computer.
Answer:
i^32=1
i^25=i
i^86=-1
i^51=-i
Step-by-step explanation:
Follow the Rule of Four of I for this,
i^1=
I^2=-1
I^3=-i
I^4=1
Let
x-------> the length side of the original cube
we have

Divide by
both sides

The system of equations is equal to
--------> equation 
--------> equation 
using a graphing tool
see the attached figure
we know that
the solution of the system of equations is the intersection both graphs
therefore
the solution is

therefore
<u>the answer is</u>

Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.