We can create the equation like this:
(x +2) * (x +0)
x^2 + 2x + 0 = 0
Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
Answer:
It is A' B'
Pls give me brainliest :)
Step-by-step explanation:
The factors of a polynomial function are the zeros of the function
It is true that x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3
<h3>How to show why the x - 3 is a factor</h3>
The function is given as:
m(x) = x^3 - x^2 - 5x - 3
The factor is given as:
x - 3
Set the factor to 0
x - 3 = 0
Solve for x
x = 3
Substitute 3 for x in the function
m(3) = 3^3 - 3^2 - 5(3) - 3
Evaluate
m(3) =0
Since the value of m(3) is 0, then x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3
Read more about factors at:
brainly.com/question/11579257
Multiply
2
2
by
5
5
.
x
5
+
10
x
4
+
10
x
3
⋅
2
2
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
10
x
3
⋅
2
2
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
2
2
.
x
5
+
10
x
4
+
10
x
3
⋅
4
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
10
x
3
⋅
4
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Multiply
4
4
by
10
10
.
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
3
3
.
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
8
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
8
+
5
x
⋅
2
4
+
2
5
Multiply
8
8
by
10
10
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
4
4
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
16
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
16
+
2
5
Multiply
16
16
by
5
5
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
2
5
Raise
2
2
to the power of
5
5
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
32
