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3 years ago

3. Find a positive and a negative coterminal angle for -260 degrees.

Mathematics

1 answer:

weqwewe [10]3 years ago

8 0

Check the picture below.

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Solve the equation for y y−5x=3

Lyrx [107]

Answer:

y = 5x + 3

Step-by-step explanation:

y - 5x = 3

add 5x to both sides to isolate y

y = 3 + 5x

rearrange to slope intercept form

y = 5x + 3

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3 years ago

Two functions are given below. How does the graph of

tensa zangetsu [6.8K]

I think it’s C. I plugged it on to a graph and shows that graph a is steeper than graph b. red is graph a. blue is graph b.

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3 years ago

Can somebody give me a Quick answer. First person gets Brainliest.

Evgen [1.6K]

Answer:D

Step-by-step explanation:

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3 years ago

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If the equation y² - (K-<br>2y + 2k +1 = 0<br>with equal roots find the value of k

777dan777 [17]

Answer:

y² - (K- 2)y + 2k +1 = 0

equal roots means D=0

D= b^2 - 4ac

a=1, b= (k-2), c= 2k+1

so,

(k-2)^2 - 4(1)(2k+1) = 0

=> k^2 +4 - 8k -4 = 0

=> k^2 -8k = 0

=> k^2 = 8k

=> k= 8k/k

=> k = 8

Therefore the answer is k= 8

Hope it helps........

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3 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

5 0

3 years ago