I need help please!!!!

Holli's house is located at (−1, 4). She can walk in a straight line to get to Jedd's house. A fast food restaurant is located a

mojhsa [17]

<h2>Answer:</h2>

The coordinate of Jedd's house is:

(-7,-2)

<h2>Step-by-step explanation:</h2>

We know that if a Point P(a,b) partitions the line joining the point (x,y) and (x',y') in the ratio m:n

Then the coordinates of the point P is given by:

$a=\dfrac{mx'+nx}{m+n},\ b=\dfrac{my'+ny}{m+n}$

Here m:n=1:2

and (a,b)=(-3,2) i.e. location of the food restaurant.

and

(x,y)=(-1,4) i.e. location of Holli's house.

and (x',y') is the location of Jedd's house.

Hence, we have:

$-3=\dfrac{1\times x'+2\times (-1)}{1+2}\ and\ 2=\dfrac{1\times y'+2\times 4}{1+2}\\\\i.e.\\\\-3=\dfrac{x'-2}{3}\ and\ 2=\dfrac{y'+8}{3}\\\\i.e.\\\\-3\times 3=x'-2\ and\ 2\times 3=y'+8\\\\i.e.\\\\-9=x'-2\ and\ 6=y'+8\\\\i.e.\\\\x'=-9+2\ and\ y'=6-8\\\\i.e.\\\\x'=-7\ and\ y'=-2$

5 0

3 years ago

Read 2 more answers

When you construct a confidence interval for the difference between two proportions, what do you use as an unbiased estimate of

Liono4ka [1.6K]

Answer:

Thus difference in sample proportions would be the unbiased estimate of the difference between the two proportions

Step-by-step explanation:

Given that you construct a confidence interval for the difference between two proportions

Let the proportions be p1 and p2

Sample sizes be n1 and n2

For samples of larger size randomly drawn we know that

p1 follows Normal with mean = sample proportion = p1 and

p2 is N with mean = sample proportion p2

Assuming these two proportions are independent we have

p1-p2 will follow a normal distribution with mean = p1-p2

Thus difference in sample proportions would be the unbiased estimate of the difference between the two proportions

3 0

3 years ago

To the nearest unit, what is the perimeter of this pentagon?

Lady bird [3.3K]

I think it might be 27 no sure

3 0

3 years ago

Read 2 more answers

Q20-23 with steps pls

just olya [345]

20: Let $x$ be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

$\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30$

Rearrange the left hand side as

$\dfrac{4x-3x}{24}=30$

And multiply both sides by 24 to get

$x=720$

21: Let $M$ and $J$ be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

$M=3J+11$

If they both get 9 more marbles, Mike will have $M+9$ marbles, and Judy will have $J+9$ marbles. So, we have

$M+J+18=93 \iff M+J=75 \iff M=75-J$

Plug this value in the first equation and we have

$75-J=3J+11 \iff 4J=64 \iff J=16$

And we deduce

$M=16\cdot 3 + 11=59$

So, the difference is

$M-J=59-16=43$

22: Let $x,y,z$ be the number of $10, $20 and $50 coupon, respectively. We're given:

$\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}
We can write the third equation by substituting the expressions for x and z:
[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38$