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Harrizon [31]
3 years ago
7

Predict whether carbon dioxide or water would have a higher boiling point. Explain your prediction in terms of the attractions b

etween molecules.
Chemistry
1 answer:
yulyashka [42]3 years ago
4 0

Answer:

since ionic bonds, bonds that are charged, have very high boiling points, then the water would have a higher boiling point because it has a slight charge whereas carbon dioxide is stable.

Explanation:

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What is the volume in liters of 321 g of liquid with a density of 0.84 g/mL
Rasek [7]
Density is weight by volume.   

First.  If you divide the weight by density you can find the volume

Second you must convert the ML in to Liters.

\frac{321 \frac{g}{1}}{0.84 \frac{g}{mL}} = \frac{321(g)(mL)}{0.84g}=\frac{321mL}{0.84}=382.14mL

1L=1000ml

\frac{1L}{1000mL}

(382.14mL)( \frac{1L}{1000mL})= \frac{(382.14mL)(L)}{1000mL} =\frac{382.14L}{1000}=0.38214L

0.38214 Liters.

4 0
3 years ago
What is the correct order of earths six convection cells , from the North Pole to the South Pole
makkiz [27]
<span>polar, Hadley, Ferrel, polar, Hadley, Ferrel. I hope this helps you.</span>
4 0
3 years ago
2. The pressure of the oxygen gas inside a
Flauer [41]

Answer: 4.41 atm

Explanation:

Given that,

Original pressure of oxygen gas (P1) = 5.00 atm

Original temperature of oxygen gas (T1) = 25°C

[Convert 25°C to Kelvin by adding 273

25°C + 273 = 298K

New pressure of oxygen gas (P2) = ?

New temperature of oxygen gas (T2) = -10°C

[Convert -10°C to Kelvin by adding 273

-10°C + 273 = 263K

Since pressure and temperature are given while volume is held constant, apply the formula for Charle's law

P1/T1 = P2/T2

5.00 atm /298K = P2/263K

To get the value of P2, cross multiply

5.00 atm x 263K = 298K x V2

1315 atm•K = 298K•V2

V2 = 1315 atm•K / 298K

V2 = 4.41 atm

Thus, the new pressure inside the canister is 4.41 atmosphere

4 0
3 years ago
Solute and solvent of C12H22O11
nasty-shy [4]

Answer:

<u>s</u><u>u</u><u>g</u><u>a</u><u>r</u> is the solute and <u>w</u><u>a</u><u>t</u><u>e</u><u>r</u> is the solvent

8 0
3 years ago
What is the reason for the low solubility of LiF (0.27 g
Brut [27]

Answer:

The answer is C. The high solvation energy for LI+

Explanation:

LiF has lower solubility because of the high solvation energy of Li+ ion. This is due to the smaller  size and very big charge compared to Cs+ ion which has a bigger size and solvent molecules easily surround it.

Solvation energy is simply the amount energy that is required to make a solute dissolve in a solvent.

3 0
3 years ago
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