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Artemon [7]
2 years ago
12

PLEASE HELP: iron reacts with nitrogen to form iron(III) nitride

Chemistry
1 answer:
lutik1710 [3]2 years ago
3 0

Answer:

2Fe +N_{2} -> 2FeN

Explanation:

Iron is Fe, nitrogen is N. Nitrogen is diatomic, which means it occurs as a molecular pair by itself. Iron III nitride has a chemical formula of FeN because nitrogen has a charge of 3-, and iron III tells us the iron has a charge of 3+ so you just need one of each to make the charges balance and the compound neutral.

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A would be correct

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A student measures the mass of a 6.0 cm3 block of brown sugar to be 10.0 g. What is the density of the brown sugar?
Alex17521 [72]

Answer:

1.67g/cm3

Explanation:

The formula for density is d=\frac{m}{v} . The m variable stands for mass and the v variable stands for volume.

The mass of the brown sugar is 10.0g and the volume is 6.0cm3, so we can plug those values into the equation.

d=\frac{10g}{6cm^{3} }

d=1.67\frac{g}{cm^{3} }

Rounded to 3 significant figures, the density of the block of brown sugar is 1.67 g/cm3. If the mass is in grams and the volume is in cm3, the unit for the final answer is \frac{g}{cm^{3} } (grams per centimetres cubed).

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3 years ago
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Answer:

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3 years ago
An element's atomic number is 7. How many protons would an atom of this element have?
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What mass in grams of a molecular substance (molar mass = 50.0 g/mol) must be added to 500 g of water to produce a solution that
Lera25 [3.4K]

<u>Answer:</u> The mass of the substance that must be added is 75.2 grams.

<u>Explanation:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{boiling point of solution}-\text{boiling point of pure solution}

\Delta T_b = ? °C

Boiling point of pure water = 100°C

Boiling point of solution = 101.54°C  

Putting values in above equation, we get:

\Delta T_b=(101.54-100)^oC=1.54^oC

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\Delta T_b=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_b = 1.54°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_b = molal boiling point elevation constant = 0.512°C/m.g

m_{solute} = Given mass of solute = ? g

M_{solute} = Molar mass of solute = 50.0 g/mol

W_{solvent} = Mass of solvent (water) = 500 g

Putting values in above equation, we get:

1.54^oC=1\times 0.512^oC/m\times \frac{m_{solute}\times 1000}{50.0g/mol\times 500}\\\\m_{solute}=\frac{1.54\times 50.0\times 500}{1\times 0.512\times 1000}=75.2g

Hence, the mass of substance that must be added is 75.2 grams.

3 0
3 years ago
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