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3 years ago

How many moles of a gas would occupy 11.4 L at 273K and 2.00 atm?

Chemistry

1 answer:

bagirrra123 [75]3 years ago

3 0

Answer:

1.02mol

Explanation:

Using the general gas equation below;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = 2.0 atm

V = 11.4L

T = 273K

n = ?

Using PV = nRT

n = PV/RT

n = 2 × 11.4/ 0.0821 × 273

n = 22.8/22.41

n = 1.017

n = 1.02mol

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If the mass of 293nv is 293.10 amu and that of 295nv is 295.45 amu , what is the atomic weight of nv?

ycow [4]

Answer;

294.13 amu

Solution;

-293nv is 293.10 amu and that of 295nv is 295.45 amu

293.05+295.2=588.25

588.25/2= 294.13 amu

an amu of 294.13 using significant figures

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3 years ago

A battery can provide a current of 4.60 A at 3.40 V for 2.50 hr. How much energy (in kJ) is produced? 1st attempt kJ Energy

Lunna [17]

Answer:

The energy produced equals 140.760 kJ

Explanation:

The relation between power, current and voltage is

$Power=Current\times Voltage$

Applying the given values in the relation above we get

$Power=4.60\times 3.40=15.64W$

Now Since $Power=\frac{Energy}{Time}\\\\Energy=Power\times Time$

Again applying the calculated values we get

$Energy=15.64\times 2.50\times 3600=140760Joules=140.76kJ$

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4 years ago

Hi guys, my question is:

guapka [62]

Answer:

See Explanation Below

Explanation:

A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.

B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5

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3 years ago

Which of the following reactions have a positive ΔSrxn? Check all that apply.

PolarNik [594]

Answer:

The reactions that have a positive ΔS rxn are the first and the fourth choices:

2A(g) + B(s) → 3C(g)

2A(g) + 2B(g) → 5C(g)

Explanation:

ΔS rxn is the change of entropy of the chemical reaction.

ΔS rxn = S after reaction - S before reaction.

Therefore, a positive ΔS rxn means that the entropy after the reaction is greater than the entropy before the reaction.

You may use some assumptions to predict whether a reaction will lead an increase or decrease of the entropy.

First, assume that all the non-shown conditions, such as temperature and pressure, are constant.

Under that assumption, and from the meaning of entropy as a measure of the disorder or randomness of a system you can predict the sign of the change of entropy.

2A(g) + B(s) → 3C(g)

1) The solid compounds, B(s) in this case, are very ordered and so they have low entropy.

2) Gas molecules are highly disordered (scattered), and the greater the number of molecules of the gas the larger the entropy, S).

Hence, since the product side shows 3 gas molecules and the reactant side shows 2 gas molecules and 1 solid molecule, you predict that the products have a larger entropy than the reactants, meaning an increase in entropy: ΔS rxn is positive.

2A(g) + B(g) → C(g)

Using the same reasoning, 3 gas molecules in the reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

A(g) + B(g) → C(g)

Again, 2 gas molecules in the reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

2A(g) + 2B(g) → 5C(g)

With the same reasoing, 5 molecules in the product side, lets you predict that will have more entropy than 4 molecules in the reactant side, and, the entropy will increase: ΔS rxn is positive.

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4 years ago

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d1i1m1o1n [39]

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neutron mass ~ 1.00866 amu

electron mass ~ 0.000549 amu

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= 0.11235amu

convert to energy, the binding energy = 1.68x10^-11 J

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3 years ago