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tatuchka [14]
3 years ago
6

Aden records the height of a stack of building blocks as he adds blocks to the top of the stack. The graph shows the height, in

Mathematics
1 answer:
Amanda [17]3 years ago
6 0
Ima guess. Dat shiii 18
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A school has a parking lot that is 150.23 feet by 135.12 feet. What is the perimeter of the parking lot?
elena-14-01-66 [18.8K]

Answer: 570.70 ft

Step-by-step explanation:

The perimeter is the distance around the entire parking lot.

The measurement of 150.23 ft by 135.12 ft is half of the distance of the lot because it represents just two sides yet there are 4 sides.

The other two sides have the same measurement as this is a rectangle.

The perimeter of the parking lot is:

= (150.23 * 2) + (135.12 * 2)

= 570.70 ft

4 0
3 years ago
Use the diagram of the right triangle above and round your answer to the nearest hundredth.
Yakvenalex [24]

Answer:

value of a = 6.93 m

hence , (b.)

Step-by-step explanation:

the given triangle is a right angled triangle, so

by using trigonometry.

=》

\tan(a)   = \tan(30)  =  \frac{1}{ \sqrt{3} }

and we know,

=》

\tan(a)  =  \frac{a}{b}

so, by above values of tan ( a ) we get,

=》

\frac{a}{b}  =  \frac{1}{ \sqrt{3} }

=》

\frac{a}{12}  =  \frac{1}{ \sqrt{3} }

=》

a = \frac{12}{ \sqrt{3} }

=》

a = 4 \sqrt{3}

=

=》

a = 6.93

hence, a = 6.93 m

4 0
3 years ago
Micheal has 5^(2) boxes. There are 5^1 of apples in each box. When empty, a box weighs 5^-2 kg. What is the total weight of boxe
Bond [772]

Answer:

5.4

Step-by-step explanation:

Juss took the test

7 0
3 years ago
What is the area of the figure shown below?
german
Área of rectangle= 18 x 14 = 252

Area or triangle=
30-18= 12
12 is the base of the triangle
14 is the height of the triangle
Area of a Triangle= 1/2bh
1/2(12)(14)=84
Área of Triangle= 84

252+84= 336

Answer= 336
4 0
2 years ago
M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
Nitella [24]

Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

      =a(x+4)(x-4i)(x+4i)

      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

      =a(x³+4x²+16x+64)

Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

\Rightarrow a = \frac{53.12}{64}

      =0.83

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

5 0
3 years ago
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