Answer:
22x?
Step-by-step explanation:
is there more to this question? if not its just simple addition and then add "x" at the end
Answer:
B. Stratified random sample is the correct answer
Answer:
A sample of 997 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
The margin of error is of:
A previous study indicates that the proportion of left-handed golfers is 8%.
This means that 
98% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?
This is n for which M = 0.02. So
Rounding up:
A sample of 997 is needed.
We know that William
paid his deductible that amount is the $150.
Then William paid 20 percent of everything else. That's 20 percent of (750
minus 150), it is equal to 150.
Then the insurance company paid 80 percent of (750 minus 250), it is equal to
480.
35a + 25c = 2660
a = 2c
35(2c) + 25c = 2660
70c + 25c = 2660
95c = 2660
c = 2660/95
c = 28 <=== there were 28 children tickets
a = 2c
a = 2(28)
a = 56 <== there were 56 adult tickets
