<u>Answer:</u> The equilibrium constant for this reaction is
<u>Explanation:</u>
The equation used to calculate standard Gibbs free change is of a reaction is:
For the given chemical reaction:
The equation for the standard Gibbs free change of the above reaction is:
We are given:
Putting values in above equation, we get:
To calculate the equilibrium constant (at 58°C) for given value of Gibbs free energy, we use the relation:
where,
= Standard Gibbs free energy = -38.2 kJ/mol = -38200 J/mol (Conversion factor: 1 kJ = 1000 J )
R = Gas constant = 8.314 J/K mol
T = temperature =
= equilibrium constant at 58°C = ?
Putting values in above equation, we get:
Hence, the equilibrium constant for this reaction is
Answer:
The answer s actually B
Explanation:
The answer is B because usatestprep said so.
Hope this helps
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B) Compound
The new volume V₂ is 5.4L
The new volume is calculated using Boyle's law formula
That is P₁V₁=P₂V₂
where,
p₁ = 852 torr
V₁ = 27.0
P₂ = 4260 torr
V₂=?
Make V₂ the subject of the formula by diving into both sides of the equation by P₂
V₂ = P₁V₁/P₂
⇒ 852 *
V₂ is, therefore, = 5.4 L
Learn more about Boyle's law here: brainly.com/question/1696010
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what happens to the energy stored in an animal is that it gets used to being process throughout the whole body for it for the body to use it and processed food and to use energy for when it goes outside