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Rama09 [41]
2 years ago
11

A sample of ideal gas at room temperature occupies a volume of 27.0 L at a pressure of 852 torr . If the pressure changes to 426

0 torr , with no change in the temperature or moles of gas, what is the new volume, V2
Chemistry
1 answer:
Lubov Fominskaja [6]2 years ago
5 0

The new volume V₂ is 5.4L

The new volume is calculated using Boyle's law formula

That  is  P₁V₁=P₂V₂

where,

p₁ =  852 torr

V₁ = 27.0

P₂ = 4260 torr

V₂=?

Make  V₂ the subject of the formula by diving into both sides of the equation by P₂

V₂ = P₁V₁/P₂

⇒ 852 *

V₂  is, therefore, = 5.4 L

Learn more about Boyle's law here: brainly.com/question/1696010

#SPJ4

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Answer:

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3 years ago
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What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10
vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, \rm pOH = 14 - pH

The pH of KOH can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the first case, the concentration of the KOH is 1. 87 \times  10^{-13}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times  10^{-13}\;\rm  M ]\\\\&= 12.73\end{aligned}

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

\rm pOH = \rm -log [OH^{-}]

The hydroxide concentration of the KOH solution is 5. 81 \times 10^{-3}\;\rm  M

Substituting value in the equation:

\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm  M ]\\\\&= 2.24 \end{aligned}

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the third case, the concentration of the NaCl is 1. 00\times 10^{-7}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times  10^{-7}\;\rm  M ]\\\\&= 7 \end{aligned}

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

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3 years ago
Based on its chemical formula, which of the following substances is an organic compound
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3 years ago
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25. How many ml of a .0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid?
Mariana [72]

Answer: There are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

Explanation:

Given: M_{1} = 0.0023 M,          V_{1} = ?

V_{2} = 15.0 mL,           M_{2} = 0.012 M

Formula used to calculate volume of strontium hydroxide solution is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.0023 M \times V_{1} = 0.012 M \times 15.0 mL\\V_{1} = 78.26 mL

Thus, we can conclude that there are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

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A person's blood type is determined by the presence and absence of specific antigens on the cell membrane. Which of these would
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Answer:

C - no antibodies

Explanation:

I dont think there is any blood type without antibodies

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