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beks73 [17]
2 years ago
12

how many 6 digit numbers can be found from digits 0,1,3,5,7,9 which are divisible by 10 and no digits is repeated​

Mathematics
1 answer:
Tanzania [10]2 years ago
8 0
It must end in a 0 for the number to be divisible by 10. The other 5 can go in any order, so 5 factorial (5!) = 5*4*3*2*1

120 numbers
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Ben strikes out 90 times in 340 at bat. What percent of the time does Ben strike out
nikklg [1K]

Answer:

percentage=26.47\%

Step-by-step explanation:

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Goryan [66]

Answer:

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Step-by-step explanation:

var y/ var x

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4 0
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Hurry show your work
Nikolay [14]

Answer: \huge\boxed{\boxed{15}}

Step-by-step explanation:

<u>Given expression</u>

\large\boxed{\frac{12[30 - (9+4^2)]}{|10|-|-6| } }

<u>Simplify the exponents</u>

\large\boxed{=\frac{12[30 - (9+16)]}{|10|-|-6| } }

Simplify values in the parenthesis

\large\boxed{=\frac{12[30 - 25]}{|10|-|-6| } }

\large\boxed{=\frac{12[5]}{|10|-|-6| } }

<u>Simplify absolute values (all positive)</u>

\large\boxed{=\frac{12[5]}{10-6 } }

\large\boxed{=\frac{12[5]}{4 } }

<u>Simplify by division</u>

\large\boxed{=3~[5]}

<u>Simplify by multiplication</u>

\huge\boxed{\boxed{=15}}

Hope this helps!! :)

Please let me know if you have any questions

7 0
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Alex787 [66]

Answer:

true

Step-by-step explanation:

its just backwards

5 0
2 years ago
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