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2 years ago

PLEASE HELP ME IM DOING A TEST Plot the inequality on the number line.

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

7 0

Answer:

I would choose the line with opens dots and put it at -2 and 4

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Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector

Feliz [49]

$f(x,y,z)=2z^2x+y^3$

$f$ has gradient

$\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k$

which at the point (-1, 4, 3) has a value of

$\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k$

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say $\vec u=15\,\vec\imath+25\,\vec\jmath$ , in which case we have

$\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}$

Then the derivative of $f$ at (-1, 4, 3) in the direction of $\vec u$ is

$D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}$

4 0

2 years ago

Find the slope of a line parallel to the line that crosses ( 3 , − 2 ) and the y -intercept is ( 0 , − 3 ) . I finally figured o

mamaluj [8]

Answer:

y = 1/3x - 3

Step-by-step explanation:

We can find the equation of the line, by finding the slope and combine with our y-intercept (-3).

We need to use the slope formula to find the slope.

Thus, we have (-3 - (-2)) / 0 - 3 = -1/-3 = 1/3

So our equation is y = -1/3x - 3

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11 months ago

Ed wants to buy a large bag of dog food for $41.00. If sales tax is 7%, how much tax will he have to pay.

Galina-37 [17]

Answer:

The answer is 43.87

Step-by-step explanation:

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2 years ago

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How I do 4 boxes that weighed total of 34 kilograms if each box had the same amount

Blizzard [7]

Each box would have exactly 8.5 kilograms each in them. Hope this helps mate =)

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2 years ago

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Read this E[2X^2 â€" Y].

djyliett [7]

Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2X ² - Y.

If you don't know how X or Y are distributed, but you know E[X ²] and E[Y], then it's as simple as distributing the expectation over the sum:

E[2X ² - Y] = 2 E[X ²] - E[Y]

Or, if you're given the expectation and variance of X, you have

Var[X] = E[X ²] - E[X]²

→ E[2X ² - Y] = 2 (Var[X] + E[X]²) - E[Y]

Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.

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2 years ago