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3 years ago

PLEASE HELP I WILL MARK BRAINLIEST!!!!!!!!!!!!

Mathematics

2 answers:

Contact [7]3 years ago

7 0

Answer:

if im wrong im sorry but i believe it is c

Step-by-step explanation:

slava [35]3 years ago

5 0

Answer:

Step-by-step explanation:

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Simplify 0.4(−4.5). −1.8 −1.65 1.65 1.8

leva [86]

The answer should be -1.8

8 0

4 years ago

What is bigger 9/2 or 8/3?

Sliva [168]

9/2 would be bigger than other 8/3

'cause we can either calculate it or can predict by the difference between numerator & denominator.

Hope it helped!

7 0

4 years ago

A 1,200g block of phosphorus-32, which has a half life of 14.3 days, is stored for 100.1 days. At the end of this period, how mu

Valentin [98]

Answer:

The amount of phosphorus-32 left after 100.1 days is 9.3 g.

Step-by-step explanation:

Given:

Initial amount of Phosphorus-32 is, $N_0=1200\ g$

Time period of decay is, $t=100.1\ days$

Half life of the block is, $t_{1/2}=14.3\ days$

Now, final amount left is, $N=?$

We know that, the decay equation for a radioactive material is given as:

$N=N_0e^{-kt}\\k\to decay\ constant$

The value of the decay constant is given as:

$k=\frac{\ln 2}{t_{1/2}}\\\\k=\frac{0.693}{14.3}=0.0485$

Now, plug in all the given values and calculate 'N'. This gives,

$N=(1200)e^{(-0.0485\times 100.1)}\\\\N=9.349\approx 9.3\ g$

Therefore, the amount of phosphorus-32 left after 100.1 days is 9.3 g

5 0

3 years ago

Help me please, please help

Sergio [31]

Answer:

Heyo. The answer is 60.48

Step-by-step explanation:

This is pretty easy, all you have to do is multiply the length, height, and width. Remember this. LxHxW. Thats is the formula. You do 4.2 cm, multiplied by 3.2 cm, then multiply that by 4.5 cm. Hope this helps! :)

8 0

4 years ago

I NEED HELP ASAP ILL GIVE 14 POINTS

Kobotan [32]

Answer:

E. 35°, 70°

Step-by-step explanation:

8 0

3 years ago

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