Question

Have to find x,y and z

Answer 1

Answer:

x=2, y=5

Step-by-step explanation:

the triangle that x is in is a right triangle (don't remember the theorem sorry)

use pythagorean theorem (a^2 + b^2 = c^2)

x is the hypotenuse(c)

1 squared plus /3 squared =c squared

1+3= c squared

4= c squared

c=2

x=2

find y using pythagorean theorem as well

/12 squared plus 2 squared = y squared

y is the hypotenuse

12+4=y squared

16= y squared

4=y

add one to account for that extra little piece

y=5

... I don't see z

Answer 2

Answer:

y= if it is the hypoteneuse for the whole triangle it √16 or 4, if it is the side of the smaller triangle it is 3

x=√4 which is 2

z= I don't think ther's a z