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cestrela7 [59]
3 years ago
7

Francesca had 20 dollars to spend on 3 gifts. She spent 8 1 4 dollars on gift A and 4 4 5 dollars on gift B. How much money did

she have left for gift C? Solve on paper to find the answer as a fraction. Then check your work on Zearn! Francesca had dollars for gift C.
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

Francesca had \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20} money left for gift C.

Step-by-step explanation:

Given:

Total money to spent on gift = $20

Money Spent on gift A = \$ 8\frac{1}{4}

\$ 8\frac{1}{4} can Rewritten as  \$\frac{33}{4}

Money Spent on gift A = \$\frac{33}{4}

Money Spent on gift B = \$ 4\frac{4}{5}

\$ 4\frac{4}{5} can Rewritten as  \$\frac{24}{5}

Money Spent on gift B = \$\frac{24}{5}

We need To find the Money left for gift C.

Solution:

Money left for gift C can be calculated by subtracting Money Spent on gift A and Money Spent on gift B with Total Money spent on gifts.

Framing in equation form we get;

Money left for gift C = 20-\frac{33}{4}-\frac{24}{5}

Now taking LCM for making the denominator common we get;

Money left for gift C =\frac{20\times 20}{20}-\frac{33\times5}{4\times5}-\frac{24\times4}{5\times4}= \frac{400}{20}-\frac{165}{20}-\frac{96}{20}=\frac{400-165-96}{20} = \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20}

Hence Francesca had \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20} money left for gift C.

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A sketch of the path of travel for the two bikers is attached for more clarifications.

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