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cestrela7 [59]
3 years ago
7

Francesca had 20 dollars to spend on 3 gifts. She spent 8 1 4 dollars on gift A and 4 4 5 dollars on gift B. How much money did

she have left for gift C? Solve on paper to find the answer as a fraction. Then check your work on Zearn! Francesca had dollars for gift C.
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

Francesca had \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20} money left for gift C.

Step-by-step explanation:

Given:

Total money to spent on gift = $20

Money Spent on gift A = \$ 8\frac{1}{4}

\$ 8\frac{1}{4} can Rewritten as  \$\frac{33}{4}

Money Spent on gift A = \$\frac{33}{4}

Money Spent on gift B = \$ 4\frac{4}{5}

\$ 4\frac{4}{5} can Rewritten as  \$\frac{24}{5}

Money Spent on gift B = \$\frac{24}{5}

We need To find the Money left for gift C.

Solution:

Money left for gift C can be calculated by subtracting Money Spent on gift A and Money Spent on gift B with Total Money spent on gifts.

Framing in equation form we get;

Money left for gift C = 20-\frac{33}{4}-\frac{24}{5}

Now taking LCM for making the denominator common we get;

Money left for gift C =\frac{20\times 20}{20}-\frac{33\times5}{4\times5}-\frac{24\times4}{5\times4}= \frac{400}{20}-\frac{165}{20}-\frac{96}{20}=\frac{400-165-96}{20} = \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20}

Hence Francesca had \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20} money left for gift C.

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Answer:

No.

Step-by-step explanation:

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Which statement proves that quadrilateral JKLM is a kite?
horsena [70]

A kite is a flat shape with straight sides. It has two pairs of equal-length adjacent (next to each other) sides.

Main properties of an arbitrary kite:

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1. Option 1 is false, because sides that are adjacent to the right angle could have different lengths or diagonals can cross not at 90°.

2. Option 2 is correct, because this option is strictly the definition of the kite.

3. Option 3 is false, because MK and LJ can be not perpendicular, and then adjacent sides will not have the same lengths.

4. Option 3 is false, because despite the perpendicularity between MK and LJ, this figure could be rhombus (with all equal sides) or square (with all equal sides and all right angles).

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Two adults and 9 students cost $50 to attend
rjkz [21]

Answer:

The cost of tickets for a play is $3.00 for adults and $2.00 for children. 350 tickets were sold and $950 was collected. How many tickets of each type were sold?

Let x = number of $3 tickets

Let y = number of $2 tickets

Total = quantity × value

Step-by-step explanation:

x + y = 350                    (equation 1)

3x + 2y = 950                 (equation 2)

Use Substitution Method

Isolate variable x in equation 1

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Substitute equation 3 into equation 2

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y = 100

Substitute y = 100 into equation 1

x + 100 = 350

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Answer: 250 $3 tickets and 100 $2 tickets were sold.

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