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3 years ago

How do you write y - 5= 3(x - 4) in slope-intercept form?

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

5 0

Answer:

B) y = 3x - 7

Step-by-step explanation:

y=mx+b

isolate y

y=3x-12+5

y=3x-7

Anni [7]3 years ago

4 0

Answer: B (y=3x-7)

Step-by-step explanation:

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Need help finding out what 3x=y and x-2y = 10

sweet-ann [11.9K]

Answer:

x=-2, y=-6

Step-by-step explanation:

Simple substitution.

Since y is isolated in one of the equations already, you can plug it into the second equation.

x - 2(3x) = 10

x - 6x = 10

-5x = 10

x = -2

Sub. x = -2 into 3x = y:

3(-2) = y

y = -6

4 0

3 years ago

Solve the inequality. <br><br>The solution is....

MAVERICK [17]

Answer:

Step-by-step explanation:

-x - 6 > 21 - 28x

27x - 6 > 21

27x > 27

x > 1

8 0

4 years ago

P(x) = x + 1x² – 34x + 343<br> d(x)= x + 9

Feliz [49]

Answer:

$x=\frac{9}{d-1},\:P=\frac{-297d+378}{\left(d-1\right)^2}+343$

Step-by-step explanation:

Let us start by isolating x for dx = x + 9.

dx - x = x + 9 - x > dx - x = 9.

Factor out the common term of x > x(d - 1) = 9.

Now divide both sides by d - 1 > $\frac{x\left(d-1\right)}{d-1}=\frac{9}{d-1};\quad \:d\ne \:1$ . Go ahead and simplify.

$x=\frac{9}{d-1};\quad \:d\ne \:1$ .

Now, $\mathrm{For\:}P=x+1x^2-34x+343, \mathrm{Subsititute\:}x=\frac{9}{d-1}$ .

$P=\frac{9}{d-1}+1\cdot \left(\frac{9}{d-1}\right)^2-34\cdot \frac{9}{d-1}+343$ .

Group the like terms... $1\cdot \left(\frac{9}{d-1}\right)^2+\frac{9}{d-1}-34\cdot \frac{9}{d-1}+343$ .

$\mathrm{Add\:similar\:elements:}\:\frac{9}{d-1}-34\cdot \frac{9}{d-1}=-33\cdot \frac{9}{d-1}$ > $1\cdot \left(\frac{9}{d-1}\right)^2-33\cdot \frac{9}{d-1}+343$ .

Now for $1\cdot \left(\frac{9}{d-1}\right)^2 > \mathrm{Apply\:exponent\:rule}: \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c} > \frac{9^2}{\left(d-1\right)^2} = 1\cdot \frac{9^2}{\left(d-1\right)^2}$ .

$\mathrm{Multiply:}\:1\cdot \frac{9^2}{\left(d-1\right)^2}=\frac{9^2}{\left(d-1\right)^2}$ .

Now for $33\cdot \frac{9}{d-1} > \mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} > \frac{9\cdot \:33}{d-1} > \frac{297}{d-1}$ .

Thus we then get $\frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}+343$ .

Now we want to combine fractions. $\frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}$ .

$\mathrm{Compute\:an\:expression\:comprised\:of\:factors\:that\:appear\:either\:in\:}\left(d-1\right)^2\mathrm{\:or\:}d-1 > This\: is \:the\:LCM > \left(d-1\right)^2$

$\mathrm{For}\:\frac{297}{d-1}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:d-1 > \frac{297}{d-1}=\frac{297\left(d-1\right)}{\left(d-1\right)\left(d-1\right)}=\frac{297\left(d-1\right)}{\left(d-1\right)^2}$

$\frac{9^2}{\left(d-1\right)^2}-\frac{297\left(d-1\right)}{\left(d-1\right)^2} > \mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}> \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$\frac{9^2-297\left(d-1\right)}{\left(d-1\right)^2} > 9^2=81 > \frac{81-297\left(d-1\right)}{\left(d-1\right)^2}$ .

Expand $81-297\left(d-1\right) > -297\left(d-1\right) > \mathrm{Apply\:the\:distributive\:law}: \:a\left(b-c\right)=ab-ac$ .

$-297d-\left(-297\right)\cdot \:1 > \mathrm{Apply\:minus-plus\:rules} > -\left(-a\right)=a > -297d+297\cdot \:1$ .

$\mathrm{Multiply\:the\:numbers:}\:297\cdot \:1=297 > -297d+297 > 81-297d+297 > \mathrm{Add\:the\:numbers:}\:81+297=378 > -297d+378 > \frac{-297d+378}{\left(d-1\right)^2}$

Therefore $P=\frac{-297d+378}{\left(d-1\right)^2}+343$ .

Hope this helps!

5 0

4 years ago

For the 1,000-meter running event, Abby's mean time is 4.5 minutes with a standard deviation of 0.75 minutes. For the 800-meter

Lilit [14]

Answer:

He performed better in the 800 m race

Step-by-step explanation:

Obtain the standardized score for each event :

Zscore = (score - mean) / standard deviation

1000 meter :

Mean = 4.5 ; Standard deviation = 0.75 ; x = 4.1

Zscore = (4.1 - 4.5) / 0.75

Zscore = - 0.4 / 0.75 = - 0.5333

800 meter :

Mean = 3.2 ; Standard deviation = 0.4 ; x = 3

Zscore = (3 - 3.2) / 0.4

Zscore = - 0.2 / 0.4 = - 0.5

-0.5 > - 0.533

Hence, he performed better in the 800 m race

3 0

3 years ago

Read 2 more answers

The graph shows the cost of buying beets at a farm stand

antiseptic1488 [7]

Answer:

Ok what's your question? cna you include the graph?

8 0

3 years ago