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sergiy2304 [10]
3 years ago
9

A certain chip W used in a circuit of a micro computer has a mass of 5.68 milligram ,calculate the amount of W in the micro comp

uter (W=28g/mol)​
Chemistry
1 answer:
Pavel [41]3 years ago
6 0

The amount of W : = 1.22 x 10²⁰

<h3>Further explanation</h3>

Given

5.6 mg of a micro computer

Required

The amount of chip

Solution

A mole is a number of particles(atoms, molecules, ions)  in a substance

1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mass = 5.68 mg = 5.68 x 10⁻³ g

mol :

= mass : MW

= 5.68 x 10⁻³ g : 28 g/mol

= 2.03 x 10⁻⁴

The number of atoms :

= 2.03 x 10⁻⁴ x 6.02.10²³

= 1.22 x 10²⁰

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Explanation:

The given data is as follows.

      P_{1} = 85 psig,   P_{2} = P_{atm} = 15 psia

        Q = 1620 gpm,  d = 2.5 inch,     l = 8 ft = 2.4384 m

According to Darey-Weisbach equation,

                        h_{l} = \frac{4fl \nu^{2}}{2gD}  ......... (1)

Value of 'f' will be decided on the basis of Reynold number.

As, it is known that R_{l} = \frac{\rho \nu d}{\mu}

where,  \mu_{water} = 10^{-3} kg/ms

As it is known that 1 gpm = \frac{1}{3.67} m^{3}/hr

So,  1 m^{3}/hr = 3.67 gpm

Therefore,   Q = 1620 \times \frac{1}{3.67}

                        = 441.4168 m^{3}/hr

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In, 1 inch = 2.54 cm = 0.0254 m

Therefore, d = 2.5 \times 0.0254 = 0.0635 m

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4 0
3 years ago
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yKpoI14uk [10]
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Answer:

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