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Harman [31]
3 years ago
15

According to the Law of Conservation of Mass, how much water is produced if 22.5 g of

Chemistry
1 answer:
nadezda [96]3 years ago
4 0

Answer: The amount of water produced is 9.3 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CH_4+2O_2\rightarrow CO_2+2H_2O

mass of reactants = mass of methane + mass of oxygen = 22.5 g + 35.7 g = 58.2 g

mass of products = mass of carbon dioxide + mass of water = 48.9 g +  mass of water

48.9 g +  mass of water = 58.2 g

mass of water = 9.3 g

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To calculate the mean, you add up all of the data values, and then divide that sum by the *number* of values.

For instance, if you wanted to find the mean score at a home run derby, and you’re given the following numbers for home runs scored by each player:

5, 4, 6, 5, 3, 1

You could calculate the mean by adding all of the score up

5 + 4 + 6 + 5 + 3 + 1 = 24

And dividing by the number of hitters (in this case, 6)

24 / 6 = 4

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7 0
3 years ago
Of the first 103 elements, how many have just ine letter in their symbol​
malfutka [58]

Answer:

14 elements.

Explanation:

B

boron

C

carbon

F

fluorine

H

hydrogen

I

iodine

N

nitrogen

O

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P

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K

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S

sulfur

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4 0
3 years ago
Part complete When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation
nikdorinn [45]

<u>Answer:</u> The isotopic symbol of barium is _{56}^{138}\textrm{Ba} and that of strontium is _{38}^{89}\textrm{Sr}

<u>Explanation:</u>

Nuclear fission reactions are defined as the reactions in which a heavier nuclei breaks down in two or more smaller nuclei.

In a nuclear reaction, the total mass and total atomic number remains the same.

  • For the given fission reaction:

^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Ba}+^{94}_{36}\textrm{Kr}+3^1_0\textrm{n}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 94 + 3

A = 139

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 36 + 0

Z = 56

The isotopic symbol of barium is _{56}^{139}\textrm{Ba}

  • For the given fission reaction:

^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Sr}+^{143}_{54}\textrm{Xe}+3^1_0\textrm{n}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 143 + 3

A = 90

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 54 + 0

Z = 38

The isotopic symbol of strontium is _{38}^{89}\textrm{Sr}

Hence, the isotopic symbol of barium is _{56}^{138}\textrm{Ba} and that of strontium is _{38}^{89}\textrm{Sr}

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3 years ago
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Answer:

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