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Harman [31]
3 years ago
15

According to the Law of Conservation of Mass, how much water is produced if 22.5 g of

Chemistry
1 answer:
nadezda [96]3 years ago
4 0

Answer: The amount of water produced is 9.3 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CH_4+2O_2\rightarrow CO_2+2H_2O

mass of reactants = mass of methane + mass of oxygen = 22.5 g + 35.7 g = 58.2 g

mass of products = mass of carbon dioxide + mass of water = 48.9 g +  mass of water

48.9 g +  mass of water = 58.2 g

mass of water = 9.3 g

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How many total moles of ions are released when the following sample dissolves completely in water?
pogonyaev

Answer:

                      8.55 × 10²⁴ Ions

Explanation:

                    Ammonium Chloride is an ionic compound which contains a monatomic anion (Cl⁻ ; Chloride) and a polyatomic cation (NH₄⁺ ; Ammonium).

Hence, when added in water Ammonium Chloride ionizes as;

                                      NH₄Cl   →    NH₄⁺  +  Cl⁻

Hence, we can say that it produces two ions when dissolved in water.

Also,

We know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of ions  contained by 7.1 moles of NH₄Cl, we will use following relation to first calculate the number of molecules as;

          Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Molecules,

          Number of Molecules  =  Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting values,

          Number of Molecules  =  7.1 mol × 6.022 × 10²³

          Number of Molecules  =  4.27 × 10²⁴ Molecules

So,

As,

                         1 Molecule of NH₄Cl contained  =  2 Ions

So,

              4.27 × 10²⁴ Molecules of NH₄Cl will contain  =  X ions

Solving for X,

                     X =  2 Ions × 4.27 × 10²⁴ Molecules / 1 Molecule

                    X =  8.55 × 10²⁴ Ions

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A first order reaction has a rate constant of 0. 543 at 25°C. Given that the activation energy is 75. 9 kj/mol. Calculate the ra
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The rate constant of first order reaction at 32. 3 °C is 0.343 /s must be less the 0. 543 at 25°C.

First-order reactions are very commonplace. we have already encountered  examples of first-order reactions: the hydrolysis of aspirin and the reaction of t-butyl bromide with water to present t-butanol. every other reaction that famous obvious first-order kinetics is the hydrolysis of the anticancer drug cisplatin.

The value of ok suggests the equilibrium ratio of products to reactants. In an equilibrium combination both reactants and merchandise co-exist. big ok > 1 merchandise are k = 1 neither reactants nor products are desired.

Rate constant K₁  = 0. 543 /s

T₁  = 25°C

Activation energy Eₐ =  75. 9 k j/mol.

T₂ = 32. 3 °C.

K₂ =?

formula;

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putting the value in the equation  

K₂ = 0.343 /s

Hence, The rate constant of first order reaction at 32. 3 °C is 0.343 /s

The specific rate steady is the proportionality consistent touching on the fee of the reaction to the concentrations of reactants. The fee law and the specific charge consistent for any chemical reaction should be determined experimentally. The cost of the charge steady is temperature established.

Learn more about activation energy here:- brainly.com/question/26724488

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