A) 1% lidocaine -x g, 0.01x pure lidocaine
5% lidocaine -y g, 0.05y pure lidocaine
(1)0.01x+0.05y=350*0.02
0.01x g we get from1% lidocoine and 0.05y g we get from 5% lidocoine
(2) x+y=350
x g is mass 1% lidocoine, we combine it with y g 5%,
so we get x+y, and we need 350g,
so x+y should be equal 350, x+y=350
we get system of 2 equations that we need to solve to find x and y
(1)0.01x+0.05y=350*0.02
(2) x+y=350
we can solve it by substitution, find x from (2) equation
x=350-y, substitute it into (1)
instead of x we put (350-y)
0.01(350-y)+0.05y=7
3.5-0.01y+0.05y=7
0.04y =3.5
y=87.5g 5% lidocaine
b)x=350-87.5=262.5 g 1% lidocaine
c) 350g =350000 mg
Answer:
A I believe
Step-by-step explanation:
Answer:
Numbers 3 and 7
Step-by-step explanation:
2163÷3= 721
2163÷6= 360.5
2163÷36= 60.08
2163÷7= 309
The answer is number 3 and 7 since both can be divided by 2163 without having remainders like number 6 and 36
Answer: 1.) 2n 2.) z+6 3.) 20 years old
Step-by-step explanation:
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<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>