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3 years ago

The limit represents the derivative of some function f at some number a. State such an f and a.

1 answer:

7 0

Limit definition of the Derivative of a function: $\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$ At x = a: $\lim_{h \to0} \frac{f(a+h)-f(a)}{h}$
If: h = x -π/4, we will have: $\lim_{h \to \pi /4} \frac{tan ( \pi /4 +h)-1}{h}$ When we compare it with a limit definition:
f( x )= tan x
f( a ) = 1
tan ( a ) = 1, a = π/4

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at a track meet,Jacob and daniel compete in 220 m hurdles. Daniels finishes in 3/4 of the a min.Jacob finishes with 5/12 of a mi

Savatey [412]

Jacob has the faster time because if you make the fractions equal you would make the denominators equal by rounding 3/4 to have a denominator of 12 making it 9/12 which is larger then 5/12 making Daniel's time slower then Jacob's.

3 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

4 years ago

What is the standard form of the line with x-intercept of 6 and y-intercept of 5?

Vanyuwa [196]

Answer:

It should be 5x-6y=30

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

F. Please answer this as soon as possible.

Liono4ka [1.6K]

Answer:

-12

Step-by-step explanation:

Convert the mixed number to an improper fraction.

-2 $\frac{2}{3}$ = $-\frac{8}{3}$

To divide, just multiply by the reciprocal.

So -2 $\frac{2}{3}$ ÷ $\frac{2}{9}$ becomes $-\frac{8}{3}$ ÷

Now you can multiply straight across.

$-\frac{8}{3}$ × $\frac{9}{2}$ = $-\frac{72}{6}$

And simplify.

$-\frac{72}{6}$ = -12

Please mark as Brainliest! :)

7 0

3 years ago

Read 2 more answers

Need help with 7 and 9 pls help

Genrish500 [490]

Answer:

<em>The remaining amount on the lunch card is $96 dollars.</em>

Hope this helps!

4 0

3 years ago