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4 months ago

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Y=5575•(0.65)^ta. What is the initial value? b. What is the decay factor?

1 answer:

Marrrta [24]4 months ago

5 0

Answer:

a) Initial Value = 5575

Decay factor = 0.35

Explanation:

The given expression is:

$Y\text{ = 5575}\times(0.65)^t$

a) What is the initial value

The initial value of Y will take place when t = 0

Substituting t = 0 into the given equation:

$Y\text{ = 5575}\times(0.65)^0$ $Y=\text{ 5575 }\times\text{ 1 = 5575}$ The initial value is Y = 5575

b) What is the decay factor

The value of a substance due to an exponential decay is given by the general expression:

$Y=A(1-r)^t$

Where A = original/Initial value, and r = decay rate

Comparing the above equation with the given equation shown below:

$Y=5575(0.65)^t$

It is clear from the comparison of both equations that A = 5575 and :

1 - r = 0.65Solving for r:r = 1 - 0.65r = 0.35The decay factor is 0.35

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Answer:

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Relation given in the question:

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