39. 8 -0.7 are multiplied together so the answer is
(-0.7)^8
= 0.05765 to nearest 100 thousandth. ( using a calculator).
40. 10^4 + 0^12 = 10,000 + 0
= 10,000
To solve this problem yo need to have the "x", the "y", and the radius. To find the radius since it is not given we use the formula.
sq rt(-3^2+1^2)
sq rt(9+1)
sq rt(10) would be the length of the radius in this case.
Then we use the sine cosine and tangent fractions
sin:y/r
cos:x/r
tan:y/x
With the values plugged in the equations are
SIN:1/sqrt(10) Since there can´t be a sq rt in hte denominator we change it to 1(sq rt(10))/10
COS:-3/sqrt(10) Since there can´t be a sq rt in the denominator we change it to -3(sq rt(10))/10
TAN:1/-3 This one can stay the same.
This would be the measures of SIN, COS, and TAN.
Answer:
20.
Given, complex number is 10+5i .
We need to find sum of the given complex number and its conjugate. The conjugate of 10+5i is 10-5i. Therefore, the sum will be 10+5i+10−5i=20.
Answer:
The area of the shaded figure is:
Step-by-step explanation:
To obtain the area of the shaded figure, first, you must calculate this as a rectangle, with the measurements: wide (4 units), and long (6 units):
- Area of a rectangle = long * wide
- Area of a rectangle = 6 * 4
- Area of a rectangle = 24 units^2
How the figure isn't a rectangle, you must subtract the triangle on the top, so, now we calculate the area of that triangle with measurements: wide (4 units), and height (2 units):
- Area of a triangle =

- Area of a triangle =

- Area of a triangle =

- Area of a triangle = 4 units^2
In the end, you subtract the area of the triangle to the area of the rectangle, to obtain the area of the shaded figure:
- Area of the shaded figure = Area of the rectangle - Area of the triangle
- Area of the shaded figure = 24 units^2 - 4 units^2
- <u>Area of the shaded figure = 20 units^2</u>
I use the name "units" because the exercise doesn't say if they are feet, inches, or another, but you can replace this in case you need it.
Answer:
C = 3b
Step-by-step explanation:
If each bottle costs 3 dollars, then the cost of b bottles would be 3b.