Answer:
x+y=2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-3-10)/(5-(-8))
m=-13/(5+8)
m=-13/13
m=-1
y-y1=m(x-x1)
y-10=-1(x-(-8))
y-10=-(x+8)
y-10=-x-8
y=-x-8+10
y=-x+2
y-(-x)=2
y+x=2
x+y=2
Answer:
$4.50
Step-by-step explanation:
We must find the unit rate.
Unit rate equals: 1 apple for 50 cents.
.5 multiplied by 9 is 4.5
Answer:
Option A is correct (17,11).
Step-by-step explanation:
6x - 9y = 3
3x - 4y =7
it can be represented in matrix form as![\left[\begin{array}{cc}6&-9\\3&4\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}3\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%26-9%5C%5C3%264%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
A= ![\left[\begin{array}{cc}6&-9\\3&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%26-9%5C%5C3%264%5Cend%7Barray%7D%5Cright%5D%20)
X= ![\left[\begin{array}{c}x\\y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D)
B= ![\left[\begin{array}{c}3\\7\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
i.e, AX=B
or X= A⁻¹ B
A⁻¹ = 1/|A| * Adj A
determinant of A = |A|= (6*-4) - (-9*3)
= (-24)-(-27)
= (-24) + 27 = 3
so, |A| = 3
Adj A= ![\left[\begin{array}{cc}-4&9\\-3&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%269%5C%5C-3%266%5Cend%7Barray%7D%5Cright%5D%20)
A⁻¹ = /3
A⁻¹ = ![\left[\begin{array}{cc}-4/3&3\\-1&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%2F3%263%5C%5C-1%262%5Cend%7Barray%7D%5Cright%5D%20)
X= A⁻¹ B
X= ![\left[\begin{array}{cc}-4/3&3\\-1&2\end{array}\right] *\left[\begin{array}{c}3\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%2F3%263%5C%5C-1%262%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
X= ![\left[\begin{array}{c}(-4/3*3) + (3*7)\\(-1*3) + (2*7)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%28-4%2F3%2A3%29%20%2B%20%283%2A7%29%5C%5C%28-1%2A3%29%20%2B%20%282%2A7%29%5Cend%7Barray%7D%5Cright%5D)
X= ![\left[\begin{array}{c}-4+21\\-3+14\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-4%2B21%5C%5C-3%2B14%5Cend%7Barray%7D%5Cright%5D)
X= ![\left[\begin{array}{c}17\\11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D17%5C%5C11%5Cend%7Barray%7D%5Cright%5D)
x= 17, y= 11
solution set= (17,11).
First, let’s find the area of the larger square. We know that the smaller square extend out 2ft and is2ft up. Well take these measures, and subtract the 2ft from the 12 ft at the top, and get 10ft, then add the 2ft to the left side, and find that it’s 6ft. We have these measures: 6ft 6ft 10ft 10ft for the larger rectangle. Let’s find the area. The are formula for a rectangle is Base(10ft) times height(6ft) . Thus 60ftsqrd. Next, let’s do the smaller rectangle. We do the same formula, 4 times 2, and get 8ftsqrd, add them together: 60ft + 8ft = 68ft!
The answer will be -28. Hope it helps
