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Marat540 [252]
3 years ago
11

Solve for x in the equation x^2-10x+25=35

Mathematics
2 answers:
Mazyrski [523]3 years ago
6 0

Answer:

\text{The solution is }x=5\pm \sqrt{35}    

Step-by-step explanation:

Given the equation

x^2-10x+25=35

we have to solve the above equation for x

x^2-10x+25=35

Subtracting 35 from both sides, we get

x^2-10x-10=0

\text{Comparing above equation with }ax^2+bx+c=0

a=1, b=-10, c=-10

By quadratic formula, the solution is

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-(-10)\pm \sqrt{(-10)^2-4(1)(-10)}}{2(1)}

x=\frac{10\pm \sqrt{100+40}}{2}

x=\frac{10 \pm \sqrt{140}}{2}

x=\frac{10 \pm 2\sqrt{35}}{2}

x=5\pm \sqrt{35}

which is required solution.

yKpoI14uk [10]3 years ago
3 0
The left side of this equation is already a perfect square:    <span>x^2-10x+25=35.

Rewriting it, we get (x-5)^2 = 35.

Taking the sqrt of both sides,    x-5 = sqrt(35).

Solving for x:    x = 5 plus or minus sqrt(35)    (answers)</span>
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Well there aren't any options but a number line pointing right with the circle being empty (For example, ○) on the point -2.

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3 years ago
M∠a=(48−x)°m∠b=(9x−38)°m∠c=90°
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Answer:

Option C:

  • m∠a = 38°
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Step-by-step explanation:

Hello!

The sum of all angles in a triangle is 180°.

Add up all the angles and solve for x by setting the equation to 180°.

<h3>Solve for x</h3>
  • ∠a + ∠b + ∠c = 180°
  • (48 - x)° + (9x - 38)° + 90° = 180°
  • 10° + 8x + 90° = 180°
  • 8x = 180° - 90° - 10°
  • 8x = 80°
  • x = 10°

Now that we solved for x, we can plug it back into each equation to solve for each angle.

<h3>Angle A</h3>
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<h3>Angle B</h3>
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  • 9(10°) - 38°
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<h3>Angle C</h3>
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The answer is Option C:

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4 0
1 year ago
Really need help on question 8.
Diano4ka-milaya [45]

Answer:50.18

Step-by-step explanation:

8x+17+9x+11=102

17x+28=102

-28. -28

17x=74

<CAD=9x+11=50.18

x=74/17

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I would approach the problem like this:

1 oz bottle.............................30cm^3
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2 years ago
The measure of c is .
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Answer:

c^2=a^2+b^2

c^2=6^2+8^2

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but still do not understand why peoples are asking that basic

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2 years ago
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