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denis-greek [22]
3 years ago
14

Please help me I love u

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0
45 is the answer have a really good day
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Answer:

Quotient means the result of division. To use guess and check to solve, you would divide different numbers by 7 until you get 9. The result is 63 ÷ 7 = 9. The quotient of sixty-three and seven is nine.

Step-by-step explanation:

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Which are the solutions to the quadratic equation x^2=9x+6
AlekseyPX
I will use a quadratic formula:

x^2=9x+6\ \ \ \ |-9x-6\\\\x^2-9x-6=0\\\\a=1;\ b=-9;\ c=-6\\\\b^2-4ac=(-9)^2-4\cdot1\cdot(-6)=81+24=105\\\\\sqrt{b^2-4ac}=\sqrt{105}\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-(-9)-\sqrt{105}}{2\cdot1}=\dfrac{9-\sqrt{105}}{2}\\\\x_2=\dfrac{-(-9)+\sqrt{105}}{2\cdot1}=\dfrac{9+\sqrt{105}}{2}
5 0
3 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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How to solve 9x^2+9x+2
Oksana_A [137]

Answer:

factoring: ( 3 x + 1 ) ( 3 x+ 2 )

expressing/equation: 9x²= 81x

81x + 9x + 2=

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Step-by-step explanation:

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