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3 years ago

The point (5, -6) is reflected over the x-axis. The coordinates of reflected point are

Mathematics

1 answer:

Stella [2.4K]3 years ago

6 0

Answer:

(5,6)

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20%5Cint%20%7Btan%7D%5E%7B3%7D%20x%20%5C%3A%20dx" id="TexFormula1" title=" \int {tan}^{3} x \

r-ruslan [8.4K]

Answer:

$\frac{ {tan}^{2} x}{2} + \ln( |cos \: x| ) + C$

Step-by-step explanation:

$\int {tan}^{3} x \: dx$

$\int \: tan \: x \times {tan}^{2} x \: dx$

$\int \: tan \: x( {sec}^{2} x - 1) \: dx$

distribute

$\int \: tan \: x \: {sec}^{2} x - tan \: x \: dx$

$\int \: tan \: x \: {sec}^{2} x \: dx \: - \int \: tan \: x \: dx$

$\int \: tan \: x \: {sec}^{2} x \: dx \: - \int \frac{sin \: x}{cos \: x} \: dx$

First integrand

let tan x = u

du = sec²x dx

Second integrand

let cos x = z

dz = -sin x dx

$= \int u \: du \: - \int - \frac{1}{z} dz$

$= \frac{ {u}^{2} }{2} + \ln( |z| ) + C$

$= \color{red}{ \boxed{ \frac{ {tan}^{2} x}{2} + \ln( |cos \: x| ) + C}}$

7 0

3 years ago

How do you find f(2x) when you know f(x) = x^3?

babymother [125]

To find the answer, you just plug 2x in place of x (even though 2x already has an x). It would look something like this: f(2x)= (2x)^3 = 2x*2x*2x= 8x^3

6 0

3 years ago

Identify the equation that describes the line in slope-intercept form.

Fittoniya [83]

Answer:

y=-2x-5

Step-by-step explanation:

slope (m)= -2, point (-4,3) put in y=mx+B

3 (y)= -2 [m](-4) + B

3=-2 (-4)+B. - multiple -2 and -4

3= 8 +B. - two negatives. multipled gives you a positive

3=8+B. - subtract 8

-8 -8

-5=b

y= -2x-5

6 0

4 years ago

The area of a circle is 43.48cm2. Find the length of the radius rounded to 2 DP.

timurjin [86]

Answer:

3.72

(its not rounded I just calculated it and got that, hope it helps:)

8 0

3 years ago

HELP!!!!!! whats the scientific notation of 30 x 10 to the power of -8

LenKa [72]

Answer:

$3 \times 10 ^{ - 7}$

4 0

3 years ago

Read 2 more answers