Jenna must run a total of 12 miles on Monday.

Find me midpoint of -9 and 6

Ymorist [56]

The answer I believe is -2. Thank you come again

4 0

3 years ago

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I need help just answer no explanation please

dimulka [17.4K]

B . sorry if i’m wrong

4 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

- 16m’n-(-25m’n)+(-7m’n)Which of the following is equivalent to the expression above?

Westkost [7]

As a rule , - times - = + and - times + = -

$\begin{gathered} -16m^2n-(-25m^2n)+(-7m^2n\text{ ) } \\ =-16m^2n+25m^2n-7m^2n\text{ ( based on the rule above )} \\ =+9m^2n-7m^2n\text{ ( -16 + 25 = + 9 )} \\ =+2m^2n \end{gathered}$

Therefore the correct answer to the question is 2m squared n

5 0

1 year ago

Tanya has a garden with a trench around it. The garden is a rectangle with length 2.5m and width 2m. The trench and the garden t

Drupady [299]

Answer:

5.5m^2

the area of just the trench is 5.5 m^2

Step-by-step explanation:

The Area of trench only is the total area(trench and garden) minus the Area of garden

Area of trench only = total area(trench and garden) - Area of garden

Area = length × breadth

Substituting the given dimensions;

Total area = 3.5 × 3 = 10.5 m^2

Area of garden = 2.5×2 = 5 m^2

Area of trench only = 10.5 m^2 - 5 m^2

Area of trench only = 5.5m^2

the area of just the trench is 5.5 m^2

8 0

3 years ago

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