To solve for the surface area of the pyramid, we make use
of the formula:
A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))
where,
l and w are the base of the pyramid = 100 mm
h is the height of the pyramid = 75 mm
Substituting the given values into the equation:
A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100
/ 2)^2 + 75^2))
A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)
A = 20,148.90 mm^2
Therefore the surface area of the pyramid is about 20,149
mm^2.
Answer:
2x²-2x-24
Step-by-step explanation:
Something has roots of 4 and -3 we can write
(x-4)(x+3)
We then attach a constant, a that will ensure that it passes through the correct point
a(x-4)(x+3)
now plug in the numbers and solve for a
a(3-4)(3+3)= -12
a(-1)(6)= -12
-6a= -12
a=2
So we have
2(x-4)(x+3)
and now it's just a matter of mulitplying/simplifying things
(x-4)(x+3)= x²-x-12
2(x²-x-12)= 2x²-2x-24
1 pack of 12 will give 4 students their pencils. 20/4 = 5
