Step-by-step explanation:
Let's say R is the initial radius of the sphere, and r is the radius at time t.
The volume of the sphere at time t is:
V = 4/3 π r³
Taking derivative with respect to radius:
dV/dr = 4π r²
This is a maximum when r is a maximum, which is when r = R.
(dV/dr)max = 4π R²
This is 4 times the sphere's initial great circle area, but not the great circle circumference. The problem statement contains an error.
X = number of servers
y = number of guests
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There must be at least 1 server for every 12 tables:
Answer is x² + 2x + 5
<u>Step-by-step explanation:</u>
Step 1:
Add the two polynomials
⇒ (2x + 7) + (x² - 2) = 2x + 7 + x² - 2 = x² + 2x + 5
Answer:
The air is .6m^3
Step-by-step explanation:
The volume of a cube is
V = s^3 where s is the side length
The volume of the tank is
V = 1^3 = 1 m^3
The volume of the water is 1 by 1 by .4
V = l*w*h
= 1 *1*.4
= .4 m^3
The difference must be filled by air
1- .4 = .6 m^3
The air is .6m^3
