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frez [133]
3 years ago
9

ASAP NO ROCKY... I NEED HELP BEFORE TIME RUNS OUT!!!!!!!!!!!!

Mathematics
2 answers:
DochEvi [55]3 years ago
7 0

Answer:

(1,-4)

Step-by-step explanation:

Lubov Fominskaja [6]3 years ago
6 0

Answer:

light blue

Step-by-step explanation:

the solution is where the two lines intersect and they intersect at (1,-4)

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Find the solutions to x2 = 28.
mr Goodwill [35]

Answer: x = \pm2\sqrt{7}\\\\

Work Shown:

x^2 = 28\\\\x = \pm\sqrt{28}\\\\x = \pm\sqrt{4*7}\\\\x = \pm\sqrt{4}*\sqrt{7}\\\\x = \pm2\sqrt{7}\\\\

This can be rewritten into x = 2\sqrt{7} \ \text{ or } \ x = -2\sqrt{7}

7 0
3 years ago
Is the equations of quadratic number pattern will always have real roots
algol [13]
No, not at all.

The general quadratic equation is

                         Ax² + Bx + C = 0 .

The roots are real only if  (B² - 4AC) is not negative.

That means if you graph it, it touches or crosses the x-axis.

If the graph is up in the air and never touches the x-axis,
then it has no real roots.
8 0
3 years ago
Which of the folleing is a statistical question?
Romashka [77]
C is the correct answer
Hope it helps!
4 0
3 years ago
On a number line suppose point E has a coordinate of -2 and EG =10 what are the possible coordinates of point G ?
galina1969 [7]

| E - G | = EG

| -2 - G | = 10

-2 - G = 10                 -2 - G = -10

   - G = 12                      - G = -8

     G = -12                       G = 8

Answer: -12 or 8

3 0
3 years ago
Select the set of equations that would be used to solve the following absolute value equation:|x-5|=20
-BARSIC- [3]
X-5= 20
x-5= -20

Absolute value makes a negative positive, so when you are solving x-5 could have been 20 originally or -20 originally. Solve for both.
7 0
4 years ago
Read 2 more answers
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