Answer:
it's b
Step-by-step explanation:
i got it right on edge
Answer:
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that the selection of the random pages will contain at least two errors is 0.2644
Step-by-step explanation:
From the information given:
Let q represent the no of typographical errors.
Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let
be the random variable that follows a Poisson distribution, then mean 
and the mean that the random selection of 50 pages will contain no error is 
∴

Pr(q =0) = 0.368
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that 50 randomly page contains at least 2 errors is computed as follows:
P(X ≥ 2) = 1 - P( X < 2)
P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2
![P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B%20%5Cdfrac%7Be%5E%7B-1%7D%201%5E0%7D%7B0%21%7D%20%2B%5Cdfrac%7Be%5E%7B-1%7D%201%5E1%7D%7B1%21%7D%20%5D)
![P(X \geq 2) = 1 - [0.3678 +0.3678]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B0.3678%20%2B0.3678%5D)

P(X ≥ 2) = 0.2644
The probability that the selection of the random pages will contain at least two errors is 0.2644
A 12 feet ramp is used to load stuff into the truck which is at a height of 3.5 feet from ground.
The ramp forms a Right triangle with ground and height of truck.
In the Right triangle, hypotenuse is 12 feet and height is 3.5 feet. We need to find horizontal base of right triangle.
We can use Pythagorean theorem that is given by :-
(Hypotenuse)² = (Base)² + (Height)²
(12)² = (Base)² + (3.5)²
144 = (Base)² + 12.25
(Base)² = 144 - 12.25
(Base)² = 131.75
(Base) = √131.75

So, horizontal distance is 11.48 feet.
Answer:
4.
Step-by-step explanation:
7n - 12 = 16
7n = 16 + 12 = 28
Since 7n = 28, n = 28 / 7 = 4.
Answer: 1537.
Step-by-step explanation:
Formula for sample size :-

Given :
Margin of error : E= 100
Critical value of 95% confidence : 
Now, the required sample size will be :-

Hence, the minimum sample size required = 1537.