Given that the die-cast has been represented by 3/16 in to 1 foot, We are are required to calculate for the actual measure of a toy measuring 6.5 inches wide and 8.5 inches long;
the actual width will be given by:
(6.5÷3/16)×1
=34.66666667
=35 feet
The actual length will be given by:
(8.5÷3/16)×1
=45.333
=45 feet
Answer:
294 cars.
Step-by-step explanation:
Let x be the number of cars and y be the number of trucks.
We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:

The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.
Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:

We can see that total number of cars sold on two dealerships will be
.
We will use substitution method to solve for x. From equation (1) we will get,

Substituting this value in equation (2) we will get,

Now let us have a common denominator.


Upon multiplying both sides of our equation by 2 we will get,





Therefore, the total number of cars sold by two dealerships is 294.
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Total area = 12 + 18 = 30cm²
(X+3)(x)(x-4)
Hope that helps :)
F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3
2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10
3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2