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Scorpion4ik [409]
4 years ago
6

AHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH C o o l​

Chemistry
1 answer:
s2008m [1.1K]4 years ago
6 0

Answer:

h

Explanation:

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If it takes 7,529 calories of heat to warm 750.0 grams of water, what was the temperature change? The specific heat of water in
Zigmanuir [339]

Answer:

The temperature change was 10.04 °C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. In this way, there is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case you know:

  • Q= 7,529 calories (cal)
  • c= 1 \frac{cal}{g*C}
  • M=750 grams

Replacing:

7,529 cal= 1  \frac{cal}{g*C} *750 g* ΔT

Solving you get:

ΔT=\frac{7,529 cal}{1 \frac{cal}{g*C}*750 g }

ΔT= 10.04 °C

So, <u><em>the temperature change was 10.04 °C.</em></u>

6 0
3 years ago
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Which Domains would you find single cell organisms
kogti [31]
Archaea and Bacteria
8 0
3 years ago
List results of Chemical Reactions.
sweet [91]

Answer:

eating

Explanation:

because when any food or anything that touches your saliva (spit) automatically a chemical reaction!

4 0
3 years ago
What is matter?
RSB [31]
The answer is would be B! :)
3 0
3 years ago
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For the simple decomposition reactionAB(g)→ A(g) + B(g)Rate =k[AB]2 and k=0.2 L/mol*s . How long will it takefor [AB] to reach 1
mixer [17]

Answer:

6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.

Explanation:

Rate = k[AB]^2

The order of the reaction is 2.

Integrated rate law for second order kinetic is:

\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt

Where, [A_0] is the initial concentration  = 1.50 mol/L

[A_t] is the final concentration  = 1/3 of initial concentration = \frac{1}{3}\times 1.50\ mol/L = 0.5 mol/L

Rate constant, k = 0.2 L/mol*s

Applying in the above equation as:-

\frac{1}{0.5} = \frac{1}{1.50}+0.2t

\frac{1}{1.5}+0.2x=\frac{1}{0.5}

t = 6.66\ s

<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>

5 0
3 years ago
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